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Trapezium rule estimations?

https://c4a3f001dcd45afe69d0ceec83003f9fbc283b2c.googledrive.com/host/0B1ZiqBksUHNYSGtmV3dzVVVvNTg/January%202015%20(IAL)%20QP%20-%20C12%20Edexcel.pdf

I don't understand question 2 part (b). I've worked out the area for part A to be 26.46 but how do I use this to make an estimation for part B?
Reply 1
Original post by jessyjellytot14
https://c4a3f001dcd45afe69d0ceec83003f9fbc283b2c.googledrive.com/host/0B1ZiqBksUHNYSGtmV3dzVVVvNTg/January%202015%20(IAL)%20QP%20-%20C12%20Edexcel.pdf

I don't understand question 2 part (b). I've worked out the area for part A to be 26.46 but how do I use this to make an estimation for part B?


Well, it's just:

Unparseable latex formula:

\displaystyle [br]\begin{equation*}\int_{2}^{11} 1 \, \mathrm{d}x+ \frac{1}{2} \int_2^{11}\frac{12}{\sqrt{x^2 - 2}} \, \mathrm{d}x \end{equation*}



from which you can easily evalaute the first part of the integral, and the second part is just half your answer to the first part.
Original post by Zacken
Well, it's just:

Unparseable latex formula:

\displaystyle [br]\begin{equation*}\int_{2}^{11} 1 \, \mathrm{d}x+ \frac{1}{2} \int_2^{11}\frac{12}{\sqrt{x^2 - 2}} \, \mathrm{d}x \end{equation*}



from which you can easily evalaute the first part of the integral, and the second part is just half your answer to the first part.


Okay thank you :smile: Is the 1dx just the difference between the two limits?
Reply 3
Original post by jessyjellytot14
Okay thank you :smile: Is the 1dx just the difference between the two limits?


Yep.

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