OCR M3 (non MEI) Wednesday 8th June

grade boundary estimates?

Reply 42

Simonium1010

7

Original post by XY123

I got 8.77

same.

Reply 43

Simonium1010

7

Original post by XY123

grade boundary estimates?

I'd Imagine it'll be around 66 for 100 UMS, 62 for 90 and 55 for an A.

Reply 44

drandy76

13

Original post by Miracle-

Yes same I got 36/73 thats 0.493.

Why would you divide by 2l for the amplitude?

To find max extension so I could find amplitude, with epe=gpe

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Reply 45

Lil_timmi

Well it's a good thing I don't require further maths for my uni offers.

Reply 46

Original post by Miracle-

I got R=73/50W, what did you get for coefficient of friction? I got like 0.49 not sure if thats right.

Last one I has some problems with too, I got 0.7m below O for centre of motion.

Yeah I got both of those, what did you get for U< for the vertical circle?

Reply 47

Nathanburns01

Original post by JoeyTr

Yeah I got both of those, what did you get for U< for the vertical circle?

I got U<Root(5ag)

Reply 48

Miracle-

2

Original post by JoeyTr

Yeah I got both of those, what did you get for U< for the vertical circle?

U<root(5ag)

Reply 49

Original post by Nathanburns01

I got U<Root(5ag)

Same here, top notch!

Reply 50

hallo.C

OP

4

Was the maximum height 5/3 a?

Reply 51

Nathanburns01

Original post by hallo.C

Was the maximum height 5/3 a?

Thats what i got

Reply 52

Original post by XY123

I got 8.77

Same here! Love it

Reply 53

drandy76

13

Original post by JoeyTr

Same here! Love it

Yes lads

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Reply 54

What was A and w for the last one?

Reply 55

dsk1898

Original post by JoeyTr

Yeah I got both of those, what did you get for U< for the vertical circle?

I'm fairly sure the question asked for a range of values of U where the string would go slack. If that is the case, then U > root(2ag), as the string must reach at least horizontal in order to go slack.

I wrote root(2ag) < U < root(5ag)

Reply 56

Original post by dsk1898

I'm fairly sure the question asked for a range of values of U where the string would go slack. If that is the case, then U > root(2ag), as the string must reach at least horizontal in order to go slack.

I wrote root(2ag) < U < root(5ag)

Strong point. I hope you're wrong but I have a feeling you're not. Hopefully 1 mark lost if so.

Reply 57

XY123