Hay everyone, Iv'e been going through all the pat papers for the exam today and there is one type of question that I become stuck on. Is there anyone that can show me HOW to solve it.
Question:
The student dissolved another small piece of the broze relic in dilute (8 mole dm-3) nitric acid. A blue solution containing Cu2^+ ions was again formed but this time a colourless gas was produced with the molecular formula NO.
Equation 4.2 reprsents the unbalanced equation for this second reaction.
Cu + H^++ NO3- ------> Cu^2+ + NO + H2O
By considering oxidaton numbers, balance equation 4.2
Answer:
3Cu + 8H^+ + 2NO3^- ----> 3Cu^2+ + 2NO + 4H2O
How did they get that equation? :s