Algebraic Fractions help

I usually know how to do them but now I've started to get a mental block.

What is an easy method to solve them? As well can people help solve these for me so that I get an idea for them myself, thanks.

1) (2x+3)/3 + 4x+1/2 = 43/2
2) (2x+3)/3 + (4x+1)/2 = 43/2x-1
3) (3x+2)/4x-2 + 2/3

I usually know how to do them but now I've started to get a mental block.

What is an easy method to solve them? As well can people help solve these for me so that I get an idea for them myself, thanks.

1) (2x+3)/3 + 4x+1/2 = 43/2
2) (2x+3)/3 + (4x+1)/2 = 43/2x-1
3) (3x+2)/4x-2 + 2/3

Common denominators:

$\displaystyle \frac{2x+3}{3} + \frac{4x+1}{2} = \frac{2(2x+3) + 3(4x+1)}{6} = \frac{43}{2}$

So do I leave the = 43/2 untouched?