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Edexcel GCSE Mathematics A Higher Paper 2016 Unofficial Markscheme

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Original post by AVFTB
How is question 11, 36%. Please can you show the working out.


120% of 30
1 - 750cm^3
2- translate over line x=-1
3- rotate 90* anticlockwise
4?
5?
6?
7?
8?
9-
10 - not enough varnish
...
21
a) a+b
b)3/4 (a+b)
same magnitude, different scaler
22
23 x=6 x=2
24- 100,25,4
25 -question is confirmed to be
3-(square root 6) over 12
Does anyone rememeber the information they gave us in the women question where the answer was11????
Reply 223
Original post by Redcoats
Yeah I got all the same answers. Does anyone remember what they got for using the graph to estimate the x^2+4x-2=0 etc.


I got -0.4 and 4.4, and -1.1 and 5.1 (I think!)

Then for the simultaneous equations I can't remember the numbers but I think there was a 4.7.
Original post by keepyourapology
the percentage question was 36%.
the number of females were 11.
the shaded area in a square was 100-25TT = 25(4-TT).


The simplified answer is 75TT because TT is a number not a variable
Reply 225
Was the vectors question 3/4 a + 3/4 b
and then the part that was like what does this tell you about point s
the answer would be that it is 3/4 along the line PT
im not too sure :/
Original post by MrsGren
was the answer to the standard form question 7x10^9
i think the question was (3.5x10^6)/(5x10^-3)
i think.. dont quote me on that


i put 7x10*8 :s-smilie:
Original post by 11ahf
Agree. Reckon the grade boundaries will be 99 for an A*, 98 for an A, 97 for a B, 96 for a C ahaha


Your banter is dead
Original post by 11tan
Q?? - Estimate 892/18.9 (or something idk) (2 marks - maybe)
Round to 1sf
900/20 = 45

Q?? - Angle = 69 (4 marks [I think])

180-48-48 = 84 (angles in a triangle sum to 180 & base angles in an isosceles are equal)
84/2 = 42 (angle at the centre is twice the angle at the circumference)
(180-42)/2 = 69 (angles in a triangle sum to 180 & base angles in an isosceles are equal)
Therefore angle = 69 (alternate segment theorem)

Q?? - Angie does not have enough varnish (5 marks)

Total area = (4x10) + (2x2.5x2) = 50 metres squared
Litres required = 50/5 = 10 litres
Angie has = 3 x 2.5 = 7.5 litres
10 litres > 7.5 litres

Q?? - find shaded area of triangles in square= 25(4 - π) (5 marks)

Square = 10x10 = 100 cm squared
Circle = π x 5 squared = 25π
Shaded = 100 - 25π = 25 (4 - π)

Q25 - find the shaded area = 3 - root6/12 (3 marks)

(root2/2 x root2/2)x 1/2 = 1/2 x 1/2 = 1/4 cm squared
(root3/3 x root2/2) x 1/2/ = root6/6 x 1/2 = root6/12 cm squared
1/4 - root6/12 = 3/12 - root6/12 = 3 - root6/12

That's all I can remember for now


for q25, would it be fine if you left as

1/4 - root6/12 ??
Reply 229
Original post by gozzabomb
someone talk about the vectors question


a+b
3b-a
3/4(a+b)
Therefore S was on OT because 3/4 is a scalar of the vector a+b.
Original post by vrajpatel
Q1 750cm^3
Q2 too vague and no timeframe
The class is a small sample/biased
Q3 p^7
g^2
k^6
10-5m
n(n-7)
45
90
No not enough varnish cos she needs 50cm^2 but has 37.5cm^2
60
T=5x+20y
(-3,-2)
11 females
100-25pi
36%
I compared median, IQR and range
150
7x10^8
X<7
7/5
2 4/5 in mixed fraction form
4/5
x=-0.4 and 4.4
X=-1.1 and 5.1
X=-1.7 and 4.7
Angle MST 69
Probability is 0.04
X=2&6
a+b
-a+3b
3/4(a+b) for vector
Point s is on both lines and it is point where they intersect
100,25,4
Final questions is (3-root6)/12


How did you get 1.7 and 4.7. I drew the graph of x+y=6 so (y=6-x) and I wrote down the points of intersection
Original post by Katmmcmillan
Does anyone rememeber the information they gave us in the women question where the answer was11????

66 people went
4 out of 10 people that went skating were male
20 people visited the art gallery
don't know what else
Original post by 11ahf
I got -0.4 and 4.4, and -1.1 and 5.1 (I think!)

Then for the simultaneous equations I can't remember the numbers but I think there was a 4.7.


Correct, I got for A -0.4 and 4.4
and B -1.1 and 4.7ish I think around there, it was <5
Reply 233
answer to the pi question?? 100-25pi
its not 75pi is it??
Can you make a foundation one please
Original post by MrsGren
would 85% be enough for an A*??


Yes, 85/100 is the boundary for an A* however this might increase or decrease based on how well the nation did as a whole
last q (3-root6)/2

second last 100 25 4 1

circle theorems is 69 degrees

does not have enough varnish

7x10^8

11 girls in art gallery

36% of ali's spending
Reply 237
Original post by MrsGren
answer to the pi question?? 100-25pi
its not 75pi is it??


No. Was 100-25pi simplifies to 25(4-pi).
Reply 238
Original post by ebaniii
for q25, would it be fine if you left as

1/4 - root6/12 ??


I'm not sure I think it said simplify as much as possible, so you may lose 1 mark :/
Original post by AVFTB
How is question 11, 36%. Please can you show the working out.


Rent % of total spending £800 Q:
800 * 30% = 240
240 + (240 * 20%) = 288
288 / 800 = 72 / 200 = 36 / 100
Rent = 36% of total spending

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