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WJEC C3/C4 8th/17th June 2016

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Reply 60
Avatar for Sznsnsn
Sznsnsn
1
Original post by Ayaz789


All you do on that one is e^3
Original post by Salamon16
No


Idek , anyone got the unofficial ms
Original post by Mango88
a and b values for transformations?



a=-5
a=3
B=-2/3
Original post by Sznsnsn
All you do on that one is e^3


http://pastpapers.download.wjec.co.uk/w14-mathematics-ms.pdf
Like look in part b , thats exactly what i did tbh
Original post by Sogolhosseini
a=-5
a=3
B=-2/3


I got a=5 & a=-3
Original post by Ayaz789



http://pastpapers.download.wjec.co.uk/s12-mathematics1-ms.pdf

Check out the answers
Reply 66
Avatar for Sznsnsn
Sznsnsn
1
Original post by Ayaz789
http://pastpapers.download.wjec.co.uk/w14-mathematics-ms.pdf
Like look in part b , thats exactly what i did tbh


That's because that one is just on its own not a power of an exponential
Original post by 98matt
What about the parametric differentiation q where you had to give the second derivative in terms of y?

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-1/y^3
Original post by Sznsnsn
That's because that one is just on its own not a power of an exponential


Well i should still get an A* hopefully considering i messed that and 5a up!
Reply 69
Avatar for Sznsnsn
Sznsnsn
1
Original post by Sogolhosseini


^^^^^
It's just times by e^3
Reply 70
Avatar for 98matt
98matt
13
Original post by FusionNetworks
-1/y^3


YES ! I had that too I think

Posted from TSR Mobile
Original post by Ayaz789
I got a=5 & a=-3


Agree
WJEC need to sort out this gardening obsession of theirs


Posted from TSR Mobile
Original post by Ayaz789
I got a=5 & a=-3



Yea yea you are right. The I forgot the the shape for a sec
Reply 74
Avatar for Mango88
Mango88
2
what did you get for d2y/d2x in terms of t
So for hh(x), was h-1(x) = h(x)?
Reply 76
Avatar for Sznsnsn
Sznsnsn
1
Original post by FusionNetworks
So for hh(x), was h-1(x) = h(x)?


Yeah and then 1/9 when subbed the value in?
Reply 77
Avatar for Mango88
Mango88
2
Original post by FusionNetworks
So for hh(x), was h-1(x) = h(x)?


Yeah I did that, and for b i got 1/9
Original post by Mango88
what did you get for d2y/d2x in terms of t


If I remember correctly: -1/8cos^3(3t)
(edited 7 years ago)
Reply 79
Avatar for Mango88
Mango88
2
What did you guys do for 2 part b?

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