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# OCR (Not MEI) S1 Wednesday 8th June 2016

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1. (Original post by samh2301)
57/58
2. were we supposed to compare the 2 different graphs for spearmans rank?
3. (Original post by metasysta)
Let's do another community MS. Please press the button to request permission to contribute.
does anyone remember roughly the marks for each part?
4. (Original post by samh2301)
Probably around the same as last year, maybe slightly lower as this paper seemed a little harder.
5. (Original post by student199919)
does anyone remember roughly the marks for each part?
Question numbers and questions would be useful too
6. 0.0864 for very last question
(Original post by metasysta)
Let's do another community MS. Please press the button to request permission to contribute.
7. (Original post by LukeBlizard)
0.0864 for very last question
I got 1.37
8. (Original post by sen99)
wouldn't it be 12 bc it said less than 140
This is probably wrong, but I got that Q1 was (something like) the 13.5th value, meaning that there are 13 values below the lower quartile
9. It was 12 as 13 was the lower quartile at 140 and it wanted values lower than 140
10. (Original post by torilee)
This is probably wrong, but I got that Q1 was (something like) the 13.5th value, meaning that there are 13 values below the lower quartile
I did too
11. (Original post by Btec certified)
I got 1.37
Lol how can a probability be more than one?
12. (Original post by Ozil5)
Haha no worries, you had to use their position on the x and y axis as ranks, so they were 12345 and 12354. I think the final answer was 0.9
I cant believe how simple it actually was ((. well there goes 5 marks. I used the wrong formula for variance but for the next part of the question i used the right method to get em2. Do you think I'll get any marks?
13. How's the BARBARA question 4/35. You already take in to account the repetitions in the first part, so you just have 1/210 as the probability.
14. (Original post by Vanilla Poison)
How's the BARBARA question 4/35. You already take in to account the repetitions in the first part, so you just have 1/210 as the probability.
this.
15. Mark Scheme: Kind of.
1)
Spearman (Given)= -1
Spearmen (Calculated)= 0.9
2)
Last Q)
P(X=3) = 0.128
P(9<X<20) = P(X≤19)-P(X≤9) = 0.120 (3sf)
3)
Marie Wins:
(0.2X0.2X0.7)+(0.2X0.2X0.3) =0.04
4)
Perm/com
A) 210
B)1/210
C)1/70
5)
Group of 12 into 3: 27,720
6)
PMCC: 0.924 Therefore more then 0.92
7) Mean N: 6.5
Total output: 20.9x12= 251
8) E(X)=2.7
VAR (X)= Forgot it but it was something obvious
9)
Coded Data
Mean: 146.5
Var= 12.8
In the range: 13 apples
Outliers: None (Marks for calculating both and saying no outliers)
Sum of M^2: 11107676.1 )Something like that, forgot it, because it's a long ****ing long number)
16. Can someone explain to me why there aren't any outliers? What I did was find the iqr (15?) then multiply that by 1.5 then add it to the uq which was 155? So then I got that 177.5-180 were outliers. Is that wrong and why?
17. What do we think that 69/72 would be approximately UMS wise?
What do we think that 69/72 would be approximately UMS wise?
Probably the full 100 ums
19. The highest Value was 176 on the box and whisker plot, so there couldn't be any outliers.
20. Guys would I lose marks for using 147 and 21.8 to find the sum of msquared instead of 146.5 and 21.75?

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