Does anyone know the answer to why acidifying bleach is dangerous question, I really didn't get it so i just put down that Nacl and Naclo are already acidic so acidifying further would give a strong acid which is dangerous as corrosive-but that seems way too simple to be correct. :/
The eq. is NaOH + Cl2 <-> ClO- + H+ + NaCL
If you add acid you incr. the conc. of H+ Ions which will cause the eq. to shift left, thus producing Cl2 which is toxic.
Hi i also made a mistake on the fermentation one and spoke about advantages and disadvantages of hydration rather than fermentation. Did u find out if we lose or gain marks as we did imply the points.
I don't know what would be the correct answer to the question but I'm assuming they wanted us to say the H+ would react with the OH- ions on the LHS which would remove them, so equilibrium would shift to the left to oppose the decrease of OH- and would produce more toxic Cl2 gas.
I fluffed up and said it would react with the NaCl to form HCl but I don't think that's right.
I don't know what would be the correct answer to the question but I'm assuming they wanted us to say the H+ would react with the OH- ions on the LHS which would remove them, so equilibrium would shift to the left to oppose the decrease of OH- and would produce more toxic Cl2 gas.
I fluffed up and said it would react with the NaCl to form HCl but I don't think that's right.
Ok cool. I just said that acidifying the solution would cause the equilibrium to shift to the left to oppose the increase in H+ ions and so the conc/moles of chlorine gas would increase and chlorine gas is toxic in high concs
hey guys im in A2, i didnt do the unit 2 test, but to summarise how did people find it? were there a lot of curveballs, like were questions weirdly written
Okay it was definitely the alcohols that we had to identify (A and B). I finished early and went through the paper to double check everything and initially I had written the aldehyde and ketone but the question definitely wanted the alcohols! Thank god i double checked!
oh crap i wrote the corresponding aldehyde and ketone ffs
What did everybody draw for the hydration of prop-1-ene mechanism? I used sulfuric acid instead of water, everybody's answer in my class conflicted with mine but using sulfuric acid is actually the technically correct mechanism.
yes bro sulfuric acid, which would then go on to form the secondary alcohol. thank god i realised otherwise i would've left the mechanism that would form a primary alcohol