C4 Binomial Expansion Help?

Show that (1+(2/x))^-1= x/(x+2)= (x/2)(1+(x/2))^-1

I managed to show the first part, but I'm not show how to use x/(x+2) to get to the second part, so please could you show me how this is done? Thanks in advance :')

Reply 1

XxKingSniprxX

21

Original post by couruthim

Show that (1+(2/x))^-1= x/(x+2)= (x/2)(1+(x/2))^-1

I managed to show the first part, but I'm not show how to use x/(x+2) to get to the second part, so please could you show me how this is done? Thanks in advance :')

post a pic so I can see what you've done / type in latex.

Inb4 Zacken saves you. :tongue:

Reply 2

poundsoffat

2

Original post by couruthim

Show that (1+(2/x))^-1= x/(x+2)= (x/2)(1+(x/2))^-1

I managed to show the first part, but I'm not show how to use x/(x+2) to get to the second part, so please could you show me how this is done? Thanks in advance :' :wink:

maybe you said this?

\left(1+\dfrac{2}{x}\right)^{-1} = \dfrac{x}{x+2} = \dfrac{x}{2} \left(1+\dfrac{x}{2}\right)^{-1}

??

Reply 3

couruthim

OP

8

Original post by poundsoffat

maybe you said this?

\left(1+\dfrac{2}{x}\right)^{-1} = \dfrac{x}{x+2} = \dfrac{x}{2} \left(1+\dfrac{x}{2}\right)^{-1}

??

Yeah, that's what I meant- sorry, I can't take a photo and don't have maths software so couldn't write it in the format shown

Reply 4

Zacken

22

Original post by couruthim

Show that (1+(2/x))^-1= x/(x+2)= (x/2)(1+(x/2))^-1

I managed to show the first part, but I'm not show how to use x/(x+2) to get to the second part, so please could you show me how this is done? Thanks in advance :' :wink:

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