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Maths question

Hi,

I'm stuck on: Solve 3 / x-1 - 4/x+2 = 2

I know 3(x+2) - 4(x-1) = 3x + 6 - 4x - 4 = 2

3x + 6 - 4x +4 = 2
//after this part... it says I'm wrong//

3x - 4x = -x
6 + 4 = 10

10 - x = 2
+ x

10 = 2 + x
-2

8 = x

answer is..
(2x + 7)(x-2) = 0
x = -7/2 x = 2

what am I getting wrong? Thanks.
Reply 1
Original post by ckfeister
Hi,

I'm stuck on: Solve 3 / x-1 - 4/x+2 = 2

I know 3(x+2) - 4(x-1) = 3x + 6 - 4x - 4 = 2

3x + 6 - 4x +4 = 2
//after this part... it says I'm wrong//

3x - 4x = -x
6 + 4 = 10

10 - x = 2
+ x

10 = 2 + x
-2

8 = x

answer is..
(2x + 7)(x-2) = 0
x = -7/2 x = 2

what am I getting wrong? Thanks.

when you times the denominators by everything you do it on both sides
Reply 2
Original post by ckfeister
Hi,

I'm stuck on: Solve 3 / x-1 - 4/x+2 = 2

I know 3(x+2) - 4(x-1) = 3x + 6 - 4x - 4 = 2

3x + 6 - 4x +4 = 2
//after this part... it says I'm wrong//

3x - 4x = -x
6 + 4 = 10

10 - x = 2
+ x

10 = 2 + x
-2

8 = x

answer is..
(2x + 7)(x-2) = 0
x = -7/2 x = 2

what am I getting wrong? Thanks.

bold is your error

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