Also for the last part of the last question, when it asks whether the natural freq will increase/decrease, i thought f was proportional to 1/root(m), thus if m increase doesn't f decrease?
with regards the atmosphere one, i remember that one kind of raio waves is deflected off the atmosphere from electronics, however couldn't remember whether it was short wave or long wave... and now cannot remember what was in the question.
Shortwave radio bounces off the atmosphere, and it's used for international broadcasting by the bbc etc.
Also for the last part of the last question, when it asks whether the natural freq will increase/decrease, i thought f was proportional to 1/root(m), thus if m increase doesn't f decrease?
was wondering wht did people get for the value of the natural frequency of the slab....i got 0.15 hz as i multipled the spring constant for each spring by 4 as there were 4 springs underneath it...
was wondering wht did people get for the value of the natural frequency of the slab....i got 0.15 hz as i multipled the spring constant for each spring by 4 as there were 4 springs underneath it...
I did the same, except that I divided the mass by 4, since each spring would have only been carrying 1/4 of it. It would have worked out the same, as k/m/4=4k/m
EDIT: although I can't remember what I actually got of course.
Also for the last part of the last question, when it asks whether the natural freq will increase/decrease, i thought f was proportional to 1/root(m), thus if m increase doesn't f decrease?
F was proportional to the square root of k/m - increasing the radius of the rod increases the stiffness constant k thus F also increases!
I think I also got 4.93Hz for the frequency in part a. As far as I know increasing the radius decreases the resistance.
F was proportional to the square root of k/m - increasing the radius of the rod increases the stiffness constant k thus F also increases!
I think I also got 4.93Hz for the frequency in part a. As far as I know increasing the radius decreases the resistance.
I can't really see that being the case. If k also increases, how do you know it increases proportional to m? if it increases slower than m then the frequency will still decrease.
I can't really see that being the case. If k also increases, how do you know it increases proportional to m? if it increases slower than m then the frequency will still decrease.