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# How do i resolve this? [M1 Edexcel]

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1. Where should the alpha angle be for Tb?
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2. Bump!!
3. since Ta and Tb have perpendicular directions and the vertical direction is perpendicular to AB (the horizontal direction), the angle you are looking for, is between the Tb and the vertical direction.
(Two acute angles with perpendicular sides are equal )
4. (Original post by depymak)
since Ta and Tb have perpendicular directions and the vertical direction is perpendicular to AB (the horizontal direction), the angle you are looking for, is between the Tb and the vertical direction.
(Two acute angles with perpendicular sides are equal )
I still don't get it?
5. Bump!!

Where should the alpha angle be for Tb?

Where should the alpha angle be for Tb?
7. An alternate method is also drawing a triangle of forces. The two cables are perpendicular, giving you a right angled triangle with 1000g as the hypotenuse. You can then use trig to find tension in A, then pythag to find tension in B.

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8. (Original post by EricPiphany)
Why is the angle (90 - a)?
Bump!!

Where should the alpha angle be for Tb?
Just a hint but you know that

What does this tell you about the triangle and the angles in the triangle?
10. (Original post by Don Pedro K.)
Why is the angle (90 - a)?
tan(alpha) = 3/4, it follows directly from this, you can spot something about the triangle
I still don't get it?
Sorry,

12. See diagram.
13. (Original post by EricPiphany)
What's the name of the 'rule' when finding α for tb
cos for Ta I know the angle is alpha because it is alternate to the α on parallel lines (Z shape)
(Original post by natninja)
Just a hint but you know that

What does this tell you about the triangle and the angles in the triangle?
I really don't know
What's the name of the 'rule' when finding α for tb
cos for Ta I know the angle is alpha because it is alternate to the αon parallel lines (Z shape)

I really don't know
Learn this, it will help if a similar thing comes up - if tan(angle) = 3/4 then it is a right angled triangle as the other side must have length 5 (so you also know that sin(angle) = 3/5 and cos(angle) = 4/5)
What's the name of the 'rule' when finding α for tb
cos for Ta I know the angle is alpha because it is alternate to the αon parallel lines (Z shape)

I really don't know

What is . Notice it's common to two right angles, so their remainders are equal.
16. (Original post by EricPiphany)

What is . Notice it's common to two right angles, so their remainders are equal.
(Original post by natninja)
Learn this, it will help if a similar thing comes up - if tan(angle) = 3/4 then it is a right angled triangle as the other side must have length 5 (so you also know that sin(angle) = 3/5 and cos(angle) = 4/5)
(Original post by OscarTG)

See diagram.
(Original post by depymak)
Sorry,
(Original post by SkyJP)
An alternate method is also drawing a triangle of forces. The two cables are perpendicular, giving you a right angled triangle with 1000g as the hypotenuse. You can then use trig to find tension in A, then pythag to find tension in B.

Posted from TSR Mobile
Thank you!!
17. Are the triangles considered to be similar triangles?
18. holy crap I just went back to the question and saw the right angle between the two cables...LOOOOOOOOOOOOL that makes things so much easier hahahaha I'm such an idiot.
19. (Original post by Don Pedro K.)
holy crap I just went back to the question and saw the right angle between the two cables...LOOOOOOOOOOOOL that makes things so much easier hahahaha I'm such an idiot.
I somehow managed to get the trig identity sin^x + cos^x = 1 in there to get the answers >.> lololl
20. i get the question but im not getting the answers, anyone got some solutions?

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