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# C2 Bearings help

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1. Hi, I am struggling with question 10 (ii) on the June 2006 OCR MEI paper. I've got as far as theta = 2 radians and I know that this is 114.6 degrees. I don't know how to go from there.
2. The original bearing was 48 degrees. So the ship has gone 114.6 degrees from this bearing in an anticlockwise direction. So this is (114.6 - 48) = 66.6 degrees ANTIclockwise from north. But remember that bearings are always taken CLOCKWISE from North so this new bearing will be (360 - 66.6) = 293.4 degrees.
3. (Original post by Teenie2)
The original bearing was 48 degrees. So the ship has gone 114.6 degrees from this bearing in an anticlockwise direction. So this is (114.6 - 48) = 66.6 degrees ANTIclockwise from north. But remember that bearings are always taken CLOCKWISE from North so this new bearing will be (360 - 66.6) = 293.4 degrees.
ahh yes! was just looking how to do this question and I didn't realise it was anticlockwise!
4. (Original post by Teenie2)
The original bearing was 48 degrees. So the ship has gone 114.6 degrees from this bearing in an anticlockwise direction. So this is (114.6 - 48) = 66.6 degrees ANTIclockwise from north. But remember that bearings are always taken CLOCKWISE from North so this new bearing will be (360 - 66.6) = 293.4 degrees.
Oh I'd forgotten that they'd given you the 48 degrees in the first part... Thanks for your help
5. just was doing this paper now as a test, and was getting 302.4, this makes more sense now

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