Edexcel(IAL) M1 June 8th 2016 Discussion

These are all the questions and parts I remember and how I did them. Please let me know If I made any errors and please add to this list because I dont remember some of the questions!


Question 1
Not sure what it was exactly but I remember finding it easy overall

Question 2
Related to the momentum of to masses before and after collision. We had to find the impulse and the mass of one of the two moving objects. I totally skipped this one.

Question 3
The two bricks falling.
So we knew that A weighed 9kg and that B weighed 1.5 kg.
A started from rest so initial velocity was 0 and its final velocity was 7m/s. The acceleration was 9.8 and using these three values we could calculate the fallen height required in the first part.
In the second part I modeled A and B together as one particle of mass 10.5 kg. This gave a downward force of 10.5g. I also used the fact that the two bricks finally came to rest so the final velocity was 0m/s and I made the assumption that there was no resistive force such that all off brick A's downward velocity as transferred to Brick B meaning that the initial velocity was 7m/s. We also knew that the bricks travelled a distance of 12cm or 0.12m. using this data i applied the formula v^2=u^2 +2as to calculate the upward acceleration or the deceleration applied to the bricks as a whole. Then using this acceleration I found the upward resistive force applied by the ground on the bricks by resolving the system in an upward direction.

Question 4
This one was about Vectors. seemed Easy but I hadn't studied this ;-;

Question 5
Diver and Springboard.
For part (a) (i) I did:
50 x 4 - 30 x 2
For Part (a)(ii) I did
50 x 3.4 - 30 x 1.4

For part (b) I used
4x - 30x2 = 5000N (I now realise I shoul have subtracted The normal reaction at C from this as well)

Question 6
The two Cars A and B.
I found T=7
So I started by using the fact that Car A had travelled (1/2 x 3,5 x 14)m in the first 3.5 seconds and then 14m each second thereafter. I then drew up a table of values of distance that A had traveled for each second after that point. I also used the formula s=ut +1/2at^2 to find an equation of motion for B becasue we knew it started from rest and had a constant acceleration of 3m/s^2. The formula simplified to s=1.5t^2. Using this answer I then calculated the distances B travelled for different values of time. At T=7 both A and B had travelled 73.5 m and so that was the point that B passed A.
I found the distance travelled by B to be= 73.5m
Drawing the graphs for this question was pretty easy.


Question 7
The two particles over a pulley and a string.
We knew that the mass of the particle on the left was 4kg and that the system was in static equilibrium.
Using this knowledge I first found the normal reaction of the particle on the left by resolving perpendicular to the slope and using R - 4gcos(a) = 0
Then using my answer I found the F(max) by using the coefficient of friction they had provided us.
From there I resolved in the direction of the tension to find the value of the tension for the particle on the left side.
I then argued that since the particle is in static equilibrium that the tension on both sides of the pulley would be the same.
Then by resolving in the direction of the tension for the particle on the right I was able to find the mass of the particle on the right which I found to be
m= 2KG!

I did the other parts too but I want to know what you guys got for it

Well thats all I remember.

Something like this: Do you remember how many marks was that Acceleration time graph?

In the first graph, the point where the two graphs intersect is that time T?

No, that's when the speeds are same.

T was meant to be the point of overtaking, (When distances are same) but I don't think any mark was allotted to it.

1 or 2 marks for Shape
1 or 2 marks for intercepts

I just lost 8 marks then, which I expected but still I'm feeling depressed.

8 marks in Finding T? the 8 marker.

Yeah, I just hope there's ECF for the rest of the question.

I'm a complete moron I used s=12 not 0.12 for the sinking question because I thought it was metres oh my lord
How many marks do you think I would lose?

I'm a complete moron I used s=12 not 0.12 for the sinking question because I thought it was metres oh my lord
How many marks do you think I would lose?

No no no I am the moron I messed up the easiest question in the test (Impulse)

Posted from TSR Mobile

i am the moron......
i used the acceleration as 9.8
i will lose the whole marks for that question

do you think they will check the method used in solving?
i mean if not why there are 8 marks?
i found a wrong answer for T and i am literally panicing

i got t as 3.7
100% sure is wrong.........
do they consider the steps even if the answer is wrong?