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# Unofficial M1 Mark Scheme?

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Why bother with a post grad? Are they even worth it? Have your say! 26-10-2016
1. ALL ANSWERS HAVE BEEN EXPLAINED - CLICK ON THE MODEL ANSWERS TAB!

IMPORTANT NOTE: After speaking with some maths teachers, they have said that they believe the grade boundaries will be relatively low due to the simultaneous vector question and question three!

*So people stop asking, when using 'g' 2 or 3 significant figures is fine.

How many marks should I give myself?
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When using an approximation such as 'g', your answers should be to three or two significant figures or you lose one 'A1' mark.
Generally, every equation you form is worth a mark (that doesn't mean you can write random equations and get marks, they have to be part of the steps to get the answer)
If you got your final answer wrong, either post in the comments how many marks you think you should get, or look up previous questions that are similar by googling 'edexecel m1 questions by topic', choosing your topic and then press CTRL + F to find a question with similar marks. Look at how the marks have been distributed and compare it to the question.
Finally, mark it twice first harshly and secondly generously so you give yourself a range of possible marks, for example 59-63 marks earned.
Question 1: (10 marks)
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1(a) 104, (3 marks)

1(b) p = (400+15t)i + (20t)j (3 marks)
q = (20t)i + (800-5t)j

1(c) Q = 640i + 640j (4 marks)

Question 2: (6 marks)
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2(a) T = 20.6N or 21N (3 marks)
2(b) 15N or 15.5N (3 marks)

Question 3: (7 marks)
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3 Ns (7 marks)

Question 4: (12 marks)
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4(a) (4 marks)

4(b) T = 8.75 s (8 marks)

Question 5: (10 marks)
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μ=0.73 or μ=0.727 (10 marks)

Question 6: (7 marks)
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d = 1.2m (4 marks)
m = 42kg (3 marks)

Question 7: (11 marks)
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7(a) F2 = 2.5i + 2.5j (7 marks)
(b) 13 ms-1 (4 marks)

Question 8: (12 marks)
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8(a) T = 11.8 N or 12 N(8 marks)

8(b) = 16.6 N or 17 N
It has a bearing of 225
or
45 degree angle between horizontal plane and vertical rope
or
draw a diagram and annotate angles (4 marks)

Model Answers: (click spoiler to show images)
Spoiler:
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.

Question Bank: (simplified)
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Question One:
Q has velocity (20i-5j) and starting position (800j). P has velocity (15i+20j) and starting location (400i).

a) Find the bearing of Q.
b) i) Find the location of P and Q at time = t.
c) Find the location of Q when it is west of P.

Question Two:
A scale pan of 0.5kg carries a brick of 1.5kg and is attached to a vertical rope. The body is accelerating upwards at 0.5m/s/s.
a) Find the tension in the rope.
b) Calculate the force exerted by the scale pan onto the brick.

Question Three:
A particle of mass 0.4kg collides with a wall at a speed of 4m/s and rebound back 5m before stopping. The coefficient of friction on the ground is 1/8. Calculate the magnitude of the impulse exerted by the wall onto the particle.

Question Four:
A car M overtakes car N at 40m/s at point A and travels for T seconds before uniformly decelerating to 0m/s at point X. Car N travels at 30m/s for 25 seconds before decelerating uniformly at the same point. AX = 975m.
a) Draw a speed-time graph of both cars on the same graph.
b) Find the value of T.

Question Five:
Particle of mass 2kg on slope inclined to ground at 20 degrees. Being pushed up a rush surface by force of 4 N at angle of 30 degrees to slope. Calculate mew.

Question Six:
Non-uniform rod of length AB has length 6m and mass 30kg. It has two supports S and T, where AS = 0.5m and TB=2m. When a particle of mass M is placed at A, the rod is at the point of tipping around S. When a particle of mass M is placed at B, the rod is at the point of tipping around T. The distance between A and the center of mass is D.
a) Find D
b) Find M

Question Seven:
F1 = (-i + 2j) F2 same direction as (i+j). Resultant of F1 and F2 has same direction as (i+3j). The resultant of F1 and F2 has acceleration (3i+9j) and initial velocity (3i-22j).
a) Calculate F2
b) Find the velocity of the resultant of F1 and F2 and t=3.

Question Eight:
Mew = 1/5. Particle A is on a horizontal plane and has mass 1.5kg. Particle B is on a verticle rope and hangs with mass 3kg. Both are connected to a pulley so that the angle between them is 90 degrees. A is to the left of B.
a) Find Tension
b)Find magnitude of tension on pulley
If you want to try and calculate your UMS score, try this:I hope you all did well!
Attached Images

2. I'll be posting model answers tomorrow (edexcel)

EDIT:

3. The coefficient question was μ=0.73
4. (Original post by particlestudent)
The coefficient question was μ=0.73
was that question 5?

1(a) 104, (90+14)

1(b) p = (400+15t)i + (20t)j
q = (20t)i + (800-5t)j

1(c) The 'j' vectors for both are equal, as it is due west.
800-5t = 20t
t = 32
therefore q = 640i + 640j

2(a) T = 20.6N
2(b) 15.45 N => 15.5 N (3sf)

3(a) Acceleration = -g/8
velocity after rebound = 3.5
thus Impulse = 3 Ns

4(a)
4(b) Area under graph = 975
Area for slower car for first 25 seconds = 750
975-750 = 225
1/2 * b * 30 =225
b = 15
total time = 15+25 = 40
so area under faster car = 975 = 1/2 * (40)(T+40)
T = 8.75 s

5) μ = 0.73

6) For 1st situation, R(T) = 0
For 2nd situation, R(S) = 0

M(S) => 0.5M = 30d-15
M(T) => M = 60 - 15d
Therefore,
d = 1.2m
M = 42kg

7(a) F2 = 2.5i + 2.5j (this required simultaneous equations)
(b) V = 12i +5j, thus speed = 13 ms-1

8(a) Fmax = 0.3g
acceleration = 0.6g
Tension = 11.76N = 11.8 N (3sf)

8(b) RF = √(11.76)^2 + (11.76)^2 = 16.6
It has a bearing of 225
6. (Original post by KloppOClock)
was that question 5?
Yes according to the person above
7. (Original post by suhaylpatel786)

1(a) 104, (90+14)

1(b) p = (400+15t)i + (20t)j
q = (20t)i + (800-5t)j

1(c) The 'j' vectors for both are equal, as it is due west.
800-5t = 20t
t = 32
therefore q = 640i + 640j

2(a) T = 20.6N
2(b) 15.45 N => 15.5 N (3sf)

3(a) Acceleration = -g/8
velocity after rebound = 3.5
thus Impulse = 3 Ns

4(a)
4(b) Area under graph = 975
Area for slower car for first 25 seconds = 750
975-750 = 225
1/2 * b * 30 =225
b = 15
total time = 15+25 = 40
so area under faster car = 975 = 1/2 * (40)(T+40)
T = 8.75 s

5) μ = 0.73

6) For 1st situation, R(T) = 0
For 2nd situation, R(S) = 0

M(S) => 0.5M = 30d-15
M(T) => M = 60 - 15d
Therefore,
d = 1.2m
M = 42kg

7(a) F2 = 2.5i + 2.5j (this required simultaneous equations)
(b) V = 12i +5j, thus speed = 13 ms-1

8(a) Fmax = 0.3g
acceleration = 0.6g
Tension = 11.76N = 11.8 N (3sf)

8(b) RF = √(11.76)^2 + (11.76)^2 = 16.6
It has a bearing of 225
These are all correct from my memory. The only contentious issue is surround 8(b), where most are uncertain as to what would qualify for the mark with regards to the direction.
8. (Original post by LukeB98)
These are all correct from my memory. The only contentious issue is surround 8(b), where most are uncertain as to what would qualify for the mark with regards to the direction.
past mark schemes have just needed to state the angle
9. (Original post by KloppOClock)
past mark schemes have just needed to state the angle
I said '45 degrees to both tensions' in words and a diagram showing R going inwards without the angle on it......
10. (Original post by particlestudent)
I said '45 degrees to both tensions' in words and a diagram showing R going inwards without the angle on it......
you may get the mark for that, I just put that the tension was at an angle of 45 degrees to the horizontal plane and vertical rope
12. (Original post by KloppOClock)
you may get the mark for that, I just put that the tension was at an angle of 45 degrees to the horizontal plane and vertical rope
Okay that's good then. I guess the only place I lost marks then was getting 1.7 for F2, I just assumed they wanted the magnitude...
13. (Original post by JamesHarper1)
i thought it was an okay paper, maybe 64 for an A?

what do you guys think?

also, does anyone remember the mark distribution of the questions?
14. (Original post by KloppOClock)
past mark schemes have just needed to state the angle
I said force acts at 45 degrees below horizontal. Would that be enough?
15. Was question 2 method: T-mg=ma? I don't remember what i put
16. (Original post by particlestudent)
Okay that's good then. I guess the only place I lost marks then was getting 1.7 for F2, I just assumed they wanted the magnitude...
well if you worked out what F2 was then did the magnitude, they may just mark your answer as correct and ignore subsequent working
17. (Original post by LukeB98)
These are all correct from my memory. The only contentious issue is surround 8(b), where most are uncertain as to what would qualify for the mark with regards to the direction.
how many marks was the moments question worth?
18. (Original post by KloppOClock)
you may get the mark for that, I just put that the tension was at an angle of 45 degrees to the horizontal plane and vertical rope
How many would you lose if you got the magnitude right but wrote 45 degrees and drew it outwards.... read the question wrong.

Also if you forgot to multiply inpulse by mass how maby would you lose?

Posted from TSR Mobile
19. (Original post by mk_98)
I said force acts at 45 degrees below horizontal. Would that be enough?
maybe, 45 degrees below horizontal could be south west or south east, if you drew a diagram with an arrow then you would get it i think
20. (Original post by KloppOClock)
well if you worked out what F2 was then did the magnitude, they may just mark your answer as correct and ignore subsequent working
I didn't work out F2 before I found the magnitude though.... My diagram had the magnitude of F1 which was root5, 2 angles and then I worked out F2 using that

I've seen one answer similar to mine but then the person mentioned something to do with parallel lines....

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