Hey all  going to try my best to create a nice markscheme for this one, off memory, so if I struggle, all help is appreciated! I thought it was a standard paper, but tricky in some areas and chucked in some abstract questions  what do you think?!
Thanks to KloppOClock for clarity on each question and for many values provided in the question  insanely good memory!
Question 1:
A nice vectors one  bit surprising to be the very first question but anyhow.
Part a) The bearing was 104 degrees (nearest whole number)
You had to do Arctan(5/20) + 90
Part b) r = ro + vt for both parts.
I believe Q = 20i5j and P = ?
Part c) West implies same J component and equating them you get T = 32 seconds
and substitute this in!
640i + 640j
Question 2:
 Triangular lift question. Mass brick = 1.5kg and lift = 0.5kg with a vertical acceleration of 1/2.
Part a) You need to look at the entire system. T2g = 2a
Therefore T = 19.6 + 1
Therefore T = 20.6N
Part B) Just look at the brick.
R1.5g = 1.5a
Therefore R = 1.5g + 0.75
Therefore R = 15.45N
Question 3  Impulse Question ( I messed up!!)
I got 3/8Ns somehow haha and used I = FT and found the force  must have done it incorrectly.
The answer is 3Ns.
Hardest question for me  I usually like impulse haha.
Question 4: Speed time Graph
Part a) 4 MARKS for a diagram was very generous. Make sure it is clearly labelled and that you clearly read the question.
Part b) 8.75 seconds
You could determine the total time via considering N:
20x35 = 750 975750 = 225
0.5 x h x b = 225
15b = 225
b =15
Therefore total time is 15 + 25 (provided in the question) = 40seconds.
So you had to equate the area and you arrived that the total time = 40seconds.
You then had to use this 40 seconds to determine T.
40 x 40t / 2 + 40xt = 975
800  20t + 40t = 975
20t = 175
t = 8.75 seconds.
I believe you found that it was constant for 8.75s at 40ms^1 and then it decelerated for 31.25 seconds.
And I double checked this and it does in fact = 975m
Question 5: Incline plane
 u= 0.727 or 0.73
40cos30 = 2gsin20 + uR
Determine the value of R and I believe it was 30 something.
Proceed to solve and you get the value of u.
The trickiest part was taking into account the fact that the force was pushing inwards against the plane.
Question 6: Moments
 Mass = 42 Kg
You had to use the idea that if point about tilting, then there must be no reaction at the other pivot.
 Distance  me and other people in my class each got different answers even though we all got the value for the mass to be the same hahaha.
I got 0.7m, others got 0.8m and 1.2m
Clarity on this one would be great! I'm assuming 1.2m
Question 7: Vectors
1. I managed to get this one I believe. You were told *lies in the direction of*  this basically implies that it is a *multiple* of the given vectors.
F1 + F2 = R and we were told that R lies in direction of (?)
You had to introduce 2 unknowns  I used psi and lambda and solve simultaneously. Quite nasty actually, edexcel really want to distinguish people  if you did not know how to do it, then that is 7 marks gone. Equate I and j components and you find lambda = 3/2 .
Using this value, F2 = 5/2i + 5/2j
2. Much more easier question, suvat with vectors.
Use V= u +at
V = 12i5j
Therefore speed = 13ms^1
Remember, it wanted speed which has no direction therefore it is the modulus of the velocity vector.
Question 8: pulley
 Create 2 equations and you find that a = 5.88ms^2
 Therefore T = 11.76
Last part:
2Tcostheta = 16.6N
Don't forget the bearing like me! 225 degrees
I think it was a decent paper, but don't be fooled by it still. It was quite demanding and you could drop marks very easily. 5662ish for an A? I guess we will see xD
There was not any pure Suvat Questions (kinematics) which was nice.
They really wanted to test knowledge on vectors.
The moments one was a pain because you had to draw it twice for 2 different scenarios.
The impulse one was abstract.
The triangular lift one was a standard lift question in disguise.
The rest was quite standard.
Please feel free to correct me/ update / provide extra information for certain questions! It is just nice to get some clarity and get a rough idea as to how you have done so you are not worrying over the summer! Thanks
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Mechanics M1 8th June  Unofficial Markscheme W/Explained Answers
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 Follow
 1
 08062016 13:09
Last edited by TrueDAN; 08062016 at 13:39. 
 Follow
 2
 08062016 13:13
Does anyone remember the actual impulse question? And their working out?
Post rating:1 
 Follow
 3
 08062016 13:16
(Original post by vvlp)
Does anyone remember the actual impulse question? And their working out?Post rating:1 
 Follow
 4
 08062016 13:23
(Original post by TrueDAN)
It was travelling 4ms and hit a wall. It rebounded 5m and experience frictional forces 1/8R I think? Im intrigued to know how this question was done as well
s=5
u=?
v=0
a=1/8
I think I got u=1.11ms^1 and then worked out mvmu. To get a value of 3Ns I feel like a value of 1.11 is wrong. 
 Follow
 5
 08062016 13:28
(Original post by vvlp)
Ahh yes! Then I used SUVAT:
s=5
u=?
v=0
a=1/8
I think I got u=1.11ms^1 and then worked out mvmu. To get a value of 3Ns I feel like a value of 1.11 is wrong. 
 Follow
 6
 08062016 13:32
(Original post by TrueDAN)
I also used suvat but must have gone wrong. It was such a weird impulse question  normally they are very straightforward and nice questions, oh well! How do you think you have done? 
 Follow
 7
 08062016 13:32
(Original post by vvlp)
Ahh yes! Then I used SUVAT:
s=5
u=?
v=0
a=1/8
I think I got u=1.11ms^1 and then worked out mvmu. To get a value of 3Ns I feel like a value of 1.11 is wrong.
then used suvat to find the speed after the collision was 3.5
0.4(3.54) = 3Ns 
 Follow
 8
 08062016 13:36
(Original post by fredgiles)
F max was 0.49 , therefore a = 1.225
then used suvat to find the speed after the collision was 3.5
0.4(3.54) = 3NsPost rating:1 
 Follow
 9
 08062016 13:39
For the last bearings question is it definitely 225? I wrote 225 and I'm fairly sure it is but some friends got 45, so just out of curiosity if anyone has a definite explanation.

 Follow
 10
 08062016 13:40
Can anyone remember the marks for each question? Did kinda crap and want to try work out if I have managed to at least scrape a grade

 Follow
 11
 08062016 13:40
(Original post by vvlp)
I got Fmax = 0.49 but can't remember what I did next; what I said was a guess. I think I did it wrong anyway. 
 Follow
 12
 08062016 13:40
And on the last question it didn't say give answer as a bearing?? Did you have to anyway, or do you think you'd still get it if you give it as a normal angle?
Post rating:1 
 Follow
 13
 08062016 13:43
(Original post by jess_12)
And on the last question it didn't say give answer as a bearing?? Did you have to anyway, or do you think you'd still get it if you give it as a normal angle? 
 Follow
 14
 08062016 13:44
(Original post by jess_12)
And on the last question it didn't say give answer as a bearing?? Did you have to anyway, or do you think you'd still get it if you give it as a normal angle? 
 Follow
 15
 08062016 13:46
(Original post by jess_12)
Can anyone remember the marks for each question? Did kinda crap and want to try work out if I have managed to at least scrape a grade
Q1  10
Q2  6
Q3  7
Q4  12
Q5  10
Q6  7
Q7  11
Q8  12 
 Follow
 16
 08062016 13:46
I won't have the other 3 as I got the tension wrong and was just hoping for the fourth but thanks for the vote of confidence

 Follow
 17
 08062016 13:47
(Original post by TrueDAN)
I will try haha!
Q1  10
Q2  6
Q3  7
Q4  12
Q5  10
Q6  7
Q7  11
Q8  12 
 Follow
 18
 08062016 13:56
(Original post by TrueDAN)
Hey all  going to try my best to create a nice markscheme for this one, off memory, so if I struggle, all help is appreciated! I thought it was a standard paper, but tricky in some areas and chucked in some abstract questions  what do you think?!
Thanks to KloppOClock for clarity on each question and for many values provided in the question  insanely good memory!
Question 1:
A nice vectors one  bit surprising to be the very first question but anyhow.
Part a) The bearing was 104 degrees (nearest whole number)
You had to do Arctan(5/20) + 90
Part b) r = ro + vt for both parts.
I believe Q = 20i5j and P = ?
Part c) West implies same J component and equating them you get T = 32 seconds
and substitute this in!
640i + 640j
Question 2:
 Triangular lift question. Mass brick = 1.5kg and lift = 0.5kg with a vertical acceleration of 1/2.
Part a) You need to look at the entire system. T2g = 2a
Therefore T = 19.6 + 1
Therefore T = 20.6N
Part B) Just look at the brick.
R1.5g = 1.5a
Therefore R = 1.5g + 0.75
Therefore R = 15.45N
Question 3  Impulse Question ( I messed up!!)
I got 3/8Ns somehow haha and used I = FT and found the force  must have done it incorrectly.
The answer is 3Ns.
Hardest question for me  I usually like impulse haha.
Question 4: Speed time Graph
Part a) 4 MARKS for a diagram was very generous. Make sure it is clearly labelled and that you clearly read the question.
Part b) 8.75 seconds
You could determine the total time via considering N:
20x35 = 750 975750 = 225
0.5 x h x b = 225
15b = 225
b =15
Therefore total time is 15 + 25 (provided in the question) = 40seconds.
So you had to equate the area and you arrived that the total time = 40seconds.
You then had to use this 40 seconds to determine T.
40 x 40t / 2 + 40xt = 975
800  20t + 40t = 975
20t = 175
t = 8.75 seconds.
I believe you found that it was constant for 8.75s at 40ms^1 and then it decelerated for 31.25 seconds.
And I double checked this and it does in fact = 975m
Question 5: Incline plane
 u= 0.727 or 0.73
40cos30 = 2gsin20 + uR
Determine the value of R and I believe it was 30 something.
Proceed to solve and you get the value of u.
The trickiest part was taking into account the fact that the force was pushing inwards against the plane.
Question 6: Moments
 Mass = 42 Kg
You had to use the idea that if point about tilting, then there must be no reaction at the other pivot.
 Distance  me and other people in my class each got different answers even though we all got the value for the mass to be the same hahaha.
I got 0.7m, others got 0.8m and 1.2m
Clarity on this one would be great! I'm assuming 1.2m
Question 7: Vectors
1. I managed to get this one I believe. You were told *lies in the direction of*  this basically implies that it is a *multiple* of the given vectors.
F1 + F2 = R and we were told that R lies in direction of (?)
You had to introduce 2 unknowns  I used psi and lambda and solve simultaneously. Quite nasty actually, edexcel really want to distinguish people  if you did not know how to do it, then that is 7 marks gone. Equate I and j components and you find lambda = 3/2 .
Using this value, F2 = 5/2i + 5/2j
2. Much more easier question, suvat with vectors.
Use V= u +at
V = 12i5j
Therefore speed = 13ms^1
Remember, it wanted speed which has no direction therefore it is the modulus of the velocity vector.
Question 8: pulley
 Create 2 equations and you find that a = 5.88ms^2
 Therefore T = 11.76
Last part:
2Tcostheta = 16.6N
Don't forget the bearing like me! 225 degrees
I think it was a decent paper, but don't be fooled by it still. It was quite demanding and you could drop marks very easily. 5662ish for an A? I guess we will see xD
There was not any pure Suvat Questions (kinematics) which was nice.
They really wanted to test knowledge on vectors.
The moments one was a pain because you had to draw it twice for 2 different scenarios.
The impulse one was abstract.
The triangular lift one was a standard lift question in disguise.
The rest was quite standard.
Please feel free to correct me/ update / provide extra information for certain questions! It is just nice to get some clarity and get a rough idea as to how you have done so you are not worrying over the summer! Thanks
Agree with most.q1  yes
q2  yes
q3  I got 3Ns. You had to work out the acceleration of the particle first using F=ma (I think a=1.225) . The with that acceleration work out v of the particle using a SUVAT. Once you had worked out v (which was 3.5 I think) you could sub it into the equation I=m(vu), hence get Impulse of 3Ns.
q4  yes
q5  yes
q6  yes  I got 1.2m and think a lot of others got 1.2m too.
q7  (a) I got part very wrong, and drew a triangle with hypotenuse of R, and managed to work out the angle opposite it. I then subbed all this (using magnitudes and Lamda and Beta as unknowns for R magnitude (so lamda root 10) and F2 magnitude (so beta root 2) into the cosine equation and got values of beta to be 6.something or 3.something (7 marks)
q7 (b) yes (4 marks)
q8  yes. I thought theta was 45 degrees so Resultant Force was 16.6N (3sf). You also had to say what direction  I put bearing of 225, and also drew a little diagram and marked it on my large diagram.
Obviously I could have and have done (like q7a) got some questions wrong. 
 Follow
 19
 08062016 13:58
(Original post by jess_12)
I won't have the other 3 as I got the tension wrong and was just hoping for the fourth but thanks for the vote of confidence 
 Follow
 20
 08062016 13:58
(Original post by JN17)
For the last bearings question is it definitely 225? I wrote 225 and I'm fairly sure it is but some friends got 45, so just out of curiosity if anyone has a definite explanation.
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Updated: June 24, 2016
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