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# How do you find the MAXIMUM mass of precipitate? :/

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1. How do you find maximum mass of precipitate?

What i did so far was that I worked out the moles:
100/1000 x 0.500= 0.05 moles
• moles x Mr = Mass

Now when it comes to Mr, is it the Mr of silver nitrate or calcium chloride?
I have tried both ways but my answer didn't match any of the options given?
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3. (Original post by huggleberry247)
nope! That's what I thought but it's 7.17 g ?!

Moles=Mass/Mr

AgCl is the ppt, think of the silver nitrate test for chloride ions, white ppt is produced.

So 100/1000 x 0.05

ANS^ x (107.9+35.5) = 7.17g
5. (Original post by Engineerrookie)
Remember moles = mass / Mr

AgCl is the ppt, think of the silver nitrate test for chloride ions, white ppt is produced.

So 100/1000 x 0.05

ANS^ x (107.9+35.5) = 7.17g
Oh I see!! Thank you!!
Oh I see!! Thank you!!

No problem! Good luck tomorrow!
7. (Original post by Engineerrookie)
No problem! Good luck tomorrow!
Thank you!!

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