You are Here: Home >< Maths

# UNOFFICIAL MARKSCHEME Edexcel Maths Calculator paper 09/06/2016

Announcements Posted on
Why bother with a post grad? Are they even worth it? Have your say! 26-10-2016
1. such an easy exam- the grade boundaries should be high
2. (Original post by thomas-cowley)
Oh f**k, I got 47.5! How did you get that? I used 1/2absinc, cosine rule and then sine rule - and triple checked it
Basically in the area of a triangle, the angle has to 'connect' the 2 lengths...

So it gave B-A = 7cm B-C = 8cm Find angle BAC

Since this didn't connect the lengths, we had to find another length, or angle... Length was the easiest

1/2 abSinC = 18
(8*7*sinC)/2 = 18
8*7*sincC = 36
Sin^-1(9/14) = 40

Then cosine rule
A^2 = 8^2 + 7^2 - 2*8*7 * cos40
A = 5.215651673

Then sine rule
A (from above) / sin40 = 8 / sinx
8(sin40) / A = sinx
X = sin^-1 (8(sin40) / A)
X =80.37
X = 80.4

Hope that helped! Even though it's a bit late now
0 is considered a significant figure when between digits. However, you would not be penalised for leaving the answer to 2dp.
Thanks, before the exam I researched significant figures and it was more complicated than I thought depending on the scenarios and stuff. Hopefully like you said they'll accept my answer, otherwise I can say good bye to the 100/100 dream.
4. (Original post by TSRRR123)
Heey,
I got exactly the same... please explain it if 40.0 was wrong
I rearranged the formula?
The question was to work out angle BAC but you must have worked out ABC and then gave that as the answer. You had to work out ABC before BAC, but you must have mistaken it and just given the wrong angle.
5. (Original post by Fez_Shabbir)
who done foundation ?
I did

QUOTE=Jf1234;65594309]What if we put 9/20 instead of 0.45 for 1b?[/QUOTE]
7. Got around 86-90 some marks I'm unsure of, I could have gotten 95 if my calculated hadn't started acting weird during the exam and hadn't doubted myself in the last question. I was just unlucky,
8. For the graph question, i plotted all the points correctly but joined them as straight lines instead of joining with a curve, will i lose marks for this?
9. (Original post by Nortexg)
Thanks, before the exam I researched significant figures and it was more complicated than I thought depending on the scenarios and stuff. Hopefully like you said they'll accept my answer, otherwise I can say good bye to the 100/100 dream.
Don't worry I'm sure it will be fine. And anyway 99/100 is still a quite reasonable score hah. Best of luck for results I'm sure you got the A* you deserve!
For the graph question, i plotted all the points correctly but joined them instead of joining with a curve, will i lose marks for this?
generally yes you would, as you learn that a x*3 graph is curved.
For the graph question, i plotted all the points correctly but joined them as straight lines instead of joining with a curve, will i lose marks for this?
I don't think so. Due to the fact that there was nothing you had to do with the graph after drawing it. If you had to work out values etc. like in the non calc that would be another story....
12. (Original post by Smileyfacecloud)
Can anyone show me the work solution for question 20? 3x^2+6x-2
13. (Original post by Nortexg)
Yeah I used the answer button and wrote down one other working fully. My final calculator answer was 80.4755... To three significant figures it's 80.48 as the 0 is not a significant figure.
In 80.48 3 s.f would be 80.5
The zero when in the middle is a significant figure. When a number is 42.20 it can be written as 42.2. As 0 is not an sf in that
14. (Original post by anna-mackinlay)
I did
Have you got the mark scheme
15. its 100% 3.8 because 3.75 rounds up to 3.8 (1dp)????

Posted from TSR Mobile
16. And whats all the confusion about the trial and error? Its 3.8
17. (Original post by Maphec)
can someone explain question 15, the car depreciation as i got the answer as yes?
He bought the car for £15000
In the first year it lost 23% of its value so, your multiplier for that part would be 0.77
15000x0.77= £11,550
Then for the next two years it lost 18%, so here your multiplier would be 0.82. So you would either do:
11,550x0.82^2=£7,766.22
Or
11,550x0.82=£9471
9471x0.82= £7,766.22

1/2 of £15000 is £7500 and £7766.22 is higher so it has not lost more than half its original value.
18. Question 7 is 3.7
Trial and improvement! 34 is closer to the 3.7 solution than the 3.8 one
19. For the last question i only worked up until finding 5.26 how many marks would i get. I counted 87 in total. If anyones looking for the paper here is the link to a yt vid but it doesnt have the 1st question and he got the bar question wrong (the answer is 3 bars)

Posted from TSR Mobile

## Register

Thanks for posting! You just need to create an account in order to submit the post
1. this can't be left blank
2. this can't be left blank
3. this can't be left blank

6 characters or longer with both numbers and letters is safer

4. this can't be left empty
1. Oops, you need to agree to our Ts&Cs to register

Updated: August 26, 2016
TSR Support Team

We have a brilliant team of more than 60 Support Team members looking after discussions on The Student Room, helping to make it a fun, safe and useful place to hang out.

This forum is supported by:
Today on TSR

### University open days

Is it worth going? Find out here

Poll
Useful resources