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# Official M1 OCR 2016 Thread

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1. (Original post by Karmen99)
Didn't you have to consider the fact that it was inclined? Meaning that g was acting at an angle?
Yeah. So when released,
Force on Q = 0.2g - Tension

Force on P = Tension - Weight component - Friction
= T - 0.2gsin30 - 0.4 x 0.2gcos30 = T - 1.659

P and Q have the same mass and the same acceleration, so the forces acting on them are equal, hence:

T - 1.659 = 0.2g - T
2T = 0.2g + 1.659

T = 1.81 N
2. what did everyone get for the coalesce particles having maximum velocity? 6.75m/s? part iii
3. (Original post by ixguard)
Yeah. So when released,
Force on Q = 0.2g - Tension

Force on P = Tension - Weight component - Friction
= T - 0.2gsin30 - 0.4 x 0.2gcos30 = T - 1.659

P and Q have the same mass and the same acceleration, so the forces acting on them are equal, hence:

T - 1.659 = 0.2g - T
2T = 0.2g + 1.659

T = 1.81 N
Same as me fam

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4. Anyone got the unofficial mark scheme
5. (Original post by duncant)
what did everyone get for the coalesce particles having maximum velocity? 6.75m/s? part iii
I got that then changed it to 4.75.
6. (Original post by duncant)
what did everyone get for the coalesce particles having maximum velocity? 6.75m/s? part iii
I got that too but I don't know if it's right
7. (Original post by AlfieH)
I got that then changed it to 4.75.
me also
8. (Original post by ixguard)
Yeah. So when released,
Force on Q = 0.2g - Tension

Force on P = Tension - Weight component - Friction
= T - 0.2gsin30 - 0.4 x 0.2gcos30 = T - 1.659

P and Q have the same mass and the same acceleration, so the forces acting on them are equal, hence:

T - 1.659 = 0.2g - T
2T = 0.2g + 1.659

T = 1.81 N
Got the same for the force on P but I considered P for before release as well, which i probably wrong... Thank you anyway! 😊
9. The minimum velocity of particle B has to be 4ms^-1, because no other collisions occur and A is travelling at 4ms^-1
10. Yeah 99% sure it was 4.75 as b had to be greater than or equal to 4 ms-1 so setting it to 4 gave desired answer

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11. (Original post by alborghetti)
Anyone got the unofficial mark scheme
there was one created and posted in another thread but I can't find it anymore!
does anyone know where it went??
12. (Original post by morrissies)
there was one created and posted in another thread but I can't find it anymore!
does anyone know where it went??
13. thank you!!
14. (Original post by drandy76)
Yeah 99% sure it was 4.75 as b had to be greater than or equal to 4 ms-1 so setting it to 4 gave desired answer

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Shoot I did that at first then crossed it out for some reason :///
15. Any idea what 68 would be UMS wise?
Any idea what 68 would be UMS wise?
Probs around full ums, not sure how difficult this paper was relative to other years though

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17. Don't think that exam was too bad tbh. A lot better than m2
18. Anyone know how many ums 66 might be??
19. (Original post by AlfieH)
I got that then changed it to 4.75.
yeah I got 4.75, as I had B going at 4
20. (Original post by tangotangopapa2)
I think it will probably be 57 for A, and 51 for B.

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