The Student Room Group

Integration

How would you integrate this?


interate.png
Reply 1
It is of the form f'(x)/f(x).
Which integrates to ln|f(x)| (+c)
There's only a very slight difference that it's multiplied by a constant, 3. But you can just take this to the left hand side of the integral.
(edited 7 years ago)
Reply 2
Original post by rpnom
How would you integrate this?


interate.png


Move the 3 outside the integral sign, then it's just f'(x) / f(x)
let u = 2x^2 - x + 2
dx/du = 1/(4x-1)

giving you the integral of
3/u du

-> 3ln(u) + c
Take the 3 from the '3(4x-1)' outside the integral then integrate using the f'(x)/f(x) rule.
Reply 5
Nice to know people agree with me.

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