Calculate the pH of the buffer solution formed when 10.00 cm3 of
0.100 mol dm–3 potassium hydroxide are added to 25.00 cm3 of 0.410 mol dm–3 ethanoic acid
I got a ph of 4.80, but the answer is 3.79. I calculated it correct up to the point of the equation, and I am still confused as to why you do no need to calculate the new CONCENTRATIONS by dividing by the new total volume of 35cm^3
Why do you find new concentrations by dividing by the total volume and when do you not?
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