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# New Maths 9-1 GCSE Sample Question HELP NEEDED!

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1. Anyone has a step by step guide on how to rearrange the following equation to make a the subject of the formula:

a + 3 = ( 2a + 7) / r

Thanks!
2. Multiply by r, the. Get all the terms with a on one side of the equation and take out a factor of a. Should be clear what to do then.
3. (Original post by B_9710)
Multiply by r, the. Get all the terms with a on one side of the equation and take out a factor of a. Should be clear what to do then.
I found the mark scheme and it says that the answer is:
a = (7 - 3r) / (r - 2)
HOW!!!
4. (Original post by NothingButWaleed)
Anyone has a step by step guide on how to rearrange the following equation to make a the subject of the formula:

a + 3 = ( 2a + 7) / r

Thanks!
1) Multiply by r....ar+3r = 2a + 7
2)Bring the ones with a to oneside... ar-2a=7-3r
3) Factor out the a....... a(r-2) = (7-3r)
4) Divide by the (r-2) to get a alone... a= (7-3r) / (r-2)

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