Maths year 11

That's right.

Oh?
Is this fine?

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BCA is the angle you want to work out.

You're given two sides, 12.8 - which is opposite to angle C and 6.8 which is adjacent to angle C

You have opposite and adjacent sides which means you use Tan, more specifically since it's an angle you use the inverse of tan.

So, arctan(12.8/6.8) = angle C



arctan just means tan^-1 just easier to denote.

Here xx



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That's correct, did you see my post about part B?

BCA is the angle you want to work out.

You're given two sides, 12.8 - which is opposite to angle C and 6.8 which is adjacent to angle C

You have opposite and adjacent sides which means you use Tan, more specifically since it's an angle you use the inverse of tan.

So, arctan(12.8/6.8) = angle C



arctan just means tan^-1 just easier to denote.

Correcto.

I didn't really understand this..

So I'm suppose to find BD

And what did X stand for ?
And where did sin come from :/

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Okay - x just represents the length of BD, it's arbitrary It could be anything.

Do you understand right angled trigonometry? (Sin Opposite side/hypothenuse Cos adjacent side/hypothenuse tan opposite side/adjacent side)


Now you're given an angle - 42 degrees and one side that is opposite from the angle which is 12.8 but we want to find the length of the hypothenuse

so the two sides involved in the equation are the opposite and the hypothenuse, this means we use sin.


so set it out: Sin(42) = 12.8 / the length of BD (in this case x)

multiply both sides by x to get xsin(42) = 12.8 - the right hand side cancels out side you're also dividing by x


Now to get x by itself divide both sides by sin(42) - since sin(42) is already being multiplied they will cancel out, leaving 12.8/sin(42)


And that's it. x = 12.8/sin(42) = 19. something

Okay - x just represents the length of BD, it's arbitrary It could be anything.

Do you understand right angled trigonometry? (Sin Opposite side/hypothenuse Cos adjacent side/hypothenuse tan opposite side/adjacent side)


Now you're given an angle - 42 degrees and one side that is opposite from the angle which is 12.8 but we want to find the length of the hypothenuse

so the two sides involved in the equation are the opposite and the hypothenuse, this means we use sin.


so set it out: Sin(42) = 12.8 / the length of BD (in this case x)

multiply both sides by x to get xsin(42) = 12.8 - the right hand side cancels out side you're also dividing by x


Now to get x by itself divide both sides by sin(42) - since sin(42) is already being multiplied they will cancel out, leaving 12.8/sin(42)


And that's it. x = 12.8/sin(42) = 19. something

Okay - x just represents the length of BD, it's arbitrary It could be anything.

Do you understand right angled trigonometry? (Sin Opposite side/hypothenuse Cos adjacent side/hypothenuse tan opposite side/adjacent side)


Now you're given an angle - 42 degrees and one side that is opposite from the angle which is 12.8 but we want to find the length of the hypothenuse

so the two sides involved in the equation are the opposite and the hypothenuse, this means we use sin.


so set it out: Sin(42) = 12.8 / the length of BD (in this case x)

multiply both sides by x to get xsin(42) = 12.8 - the right hand side cancels out side you're also dividing by x


Now to get x by itself divide both sides by sin(42) - since sin(42) is already being multiplied they will cancel out, leaving 12.8/sin(42)


And that's it. x = 12.8/sin(42) = 19. something

What about this question?


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Best advice i could give DO PAST PAPERS its the best way to get better a maths. Any topics you dont get use sites like mathswatch.

And this.

If you just explain them so I can do them tonight or tomorrow morning xx



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And this.

If you just explain them so I can do them tonight or tomorrow morning xx



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$x=4.3 \cos 50^{\circ}$.

Might as well write the answer out while you're at it...

try use pythagorus.

A bit stuck.


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