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# Maths year 11

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1. (Original post by RDKGames)
Correct.

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2. (Original post by z_o_e)

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AJF is an isosceles triangle, and the angle at J is the interior angle of the pentagon. Use colours if it makes it easier for you with the haxagon and pentagon. Within the isosceles triangle, the two other ones are equal. So now you can shift your focus on the angle at A. You found the interior of the hexagon so you can use this to work out the angle BAJ. This is very similar to that double pentagon question.
3. (Original post by RDKGames)
AJF is an isosceles triangle, and the angle at J is the interior angle of the pentagon. Use colours if it makes it easier for you with the haxagon and pentagon. Within the isosceles triangle, the two other ones are equal. So now you can shift your focus on the angle at A. You found the interior of the hexagon so you can use this to work out the angle BAJ. This is very similar to that double pentagon question.

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5. Yep you got that angle of 36, you can now use this to work out the angle BAJ. Remember, BAJ does not mean you must find and state the angles at B, A and J.
6. (Original post by RDKGames)
Yep you got that angle of 36, you can now use this to work out the angle BAJ. Remember, BAJ does not mean you must find and state the angles at B, A and J.
Oh? How do I find baj?

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7. (Original post by z_o_e)
Oh? How do I find baj?

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It's this angle here that I've marked in red. When you see something like 'angle ABC' imagine yourself starting at A, going to B and then going to C; and this angle at B between the paths AB and BC is what is referred to as 'angle ABC'.

You can see that the angle from the isosceles triangle, along with the red angle BAJ, make up the interior angle of the hexagon.

8. (Original post by z_o_e)
Oh? How do I find baj?

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You could do180 - angle JAH or the interior angle of a regular hexagon - angle JAF
9. (Original post by 34908seikj)
You could do180 - angle JAH or the interior angle of a regular hexagon - angle JAF
does it say BAH lies on a striaght line? if not I dont think you can 180- JAH

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10. (Original post by 34908seikj)
You could do180 - angle JAH or the interior angle of a regular hexagon - angle JAF
You would have to prove that BAH is a straight line for that (spoilers: it isn't). And the second one is what I'm trying to get her to do, so keep those spoilers to yourself
11. (Original post by RDKGames)
You would have to prove that BAH is a straight line for that (spoilers: it isn't). And the second one is what I'm trying to get her to do, so keep those spoilers to yourself
I got 84 degrees

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12. (Original post by z_o_e)
I got 84 degrees

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Yep.
13. (Original post by RDKGames)
Yep.

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14. I could do area of packet and area of container.

The total of packet ÷ by area of container?

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15. (Original post by z_o_e)
I could do area of packet and area of container.

The total of packet ÷ by area of container?

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Firstly; it's the volume that we are talking about, not the area.
Secondly; the calculation should be the other way around because we want to know how many packets go into the container, so we are dividing the volume of the container INTO the volume of each packet.
16. (Original post by RDKGames)
Firstly; it's the volume that we are talking about, not the area.
Secondly; the calculation should be the other way around because we want to know how many packets go into the container, so we are dividing the volume of the container BY the volume of each packet.

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17. Volume of container / volume of each packet. Be careful of units though.
18. Correct volumes, but units have to be the same in order to do operations with them.
19. (Original post by B_9710)
Volume of container / volume of each packet. Be careful of units though.

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20. (Original post by RDKGames)
Correct volumes, but units have to be the same in order to do operations with them.
Yepp changed them to CM

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