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# Maths year 11

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1. (Original post by RDKGames)
Alright turn these into fractions:

(a) 0.145

EXAMPLE:

(b) 0.1

(c) 0.65

(d) 0.841

..and a bit more challenging in the mix

(e)
What did you do after 145/1000 the 29 bit I didn't understand it.
2. (Original post by RDKGames)
Alright turn these into fractions:

(a) 0.145

EXAMPLE:

(b) 0.1

(c) 0.65

(d) 0.841

..and a bit more challenging in the mix

(e)

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3. (Original post by z_o_e)
What did you do after 145/1000 the 29 bit I didn't understand it.
I divided top and bottom by 5 in order to simplify it down.
4. (Original post by RDKGames)
I divided top and bottom by 5 in order to simplify it down.

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5. Looks good. Though for the first one it should be 200, not 100, on the denominator.
6. (Original post by RDKGames)
Looks good. Though for the first one it should be 200, not 100, on the denominator.
What do I do with the 841 one?

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7. (Original post by z_o_e)
What do I do with the 841 one?

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Just leave it as it is. 841 is a prime number so you cannot reduce that fraction any further.

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8. (Original post by RDKGames)
Just leave it as it is. 841 is a prime number so you cannot reduce that fraction any further.

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9. (Original post by z_o_e)

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Slightly trickier method:

x=0.333....
10x=3.333...
---------------------------
Take x away from 10x
9x=3
x=3/9=1/3=0.333....
10. (Original post by RDKGames)
Slightly trickier method:

x=0.333....
10x=3.333...
---------------------------
Take x away from 10x
9x=3
x=3/9=1/3=0.333....
I don't understand where X and 10 comes from and how you work it out?
11. (Original post by z_o_e)
I don't understand where X and 10 comes from and how you work it out?
That's the trick.

If we let then we can get 10x by multiplying both sides by 10; hence where 3.333... comes from. Then when we subtract x from 10x, all the decimal places cancel out and we are left with 3 because 3.333... - 0.333... = 3
12. (Original post by RDKGames)
That's the trick.

If we let then we can get 10x by multiplying both sides by 10; hence where 3.333... comes from. Then when we subtract x from 10x, all the decimal places cancel out and we are left with 3 because 3.333... - 0.333... = 3
Can you do more examples of these please on a piece of paper?
13. (Original post by RDKGames)
That's the trick.

If we let then we can get 10x by multiplying both sides by 10; hence where 3.333... comes from. Then when we subtract x from 10x, all the decimal places cancel out and we are left with 3 because 3.333... - 0.333... = 3
You could consider the sum of the geometric series .
14. (Original post by z_o_e)
Can you do more examples of these please on a piece of paper?
Try finding fraction equivalent to .
15. (Original post by Ano123)
You could consider the sum of the geometric series .
I could. But I choose not to for a GCSE student.
16. (Original post by RDKGames)
I could. But I choose not to for a GCSE student.
Yah I know but I bet you never considered it this way before.
17. (Original post by z_o_e)
Can you do more examples of these please on a piece of paper?
Try turning these into fractions and use the examples below for help:

(a)
(b)
(c)
(c)
Spoiler:
Show

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18. (Original post by RDKGames)
Try turning these into fractions and use the examples below for help:

(a)
(b)
(c)
(c)
Spoiler:
Show

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I will do those in a bit

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19. (Original post by z_o_e)
I will do those in a bit

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Good

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20. I was the same in year 10, I didn't realise how important Maths was until I was halfway through year 11. I was getting D's and C's in year 10 and half of year 11, but in January I realised I was under achieving and I was doubting my abilities, so from January I started working on the subject I found most difficult, and even though I didn't like my teacher I asked for her help, and I was persistant with my studying at home and I was achieving high B's and well onto A's by the time I sat my exams in June, so you can do it. My best advice is to practise exam paper questions and always practise the topics you find most difficult. Good Luck 😄

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