1.0.994
w=0.721 + 0.0142d
5.691 response was wiggle
2.p=0.175 q=0.15
varx=2.115
E (r) was 0.45 rebecca and sarah winning 0.475 0.375
3. 2.35 133.9 0.754
4.0 0.03 0.22 0.45 0.405 33 was number of diners
5. K=0.5
h=17
med=3.47
0.68
0.2546
6. 0.0668
206.336
0.36
Feel free to correct or give answers to non numerical questions
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Edexcel s1 June 2016 unofficial mark scheme
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 1
 15062016 11:47
Last edited by gladheateher; 15062016 at 11:51.Post rating:2 
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 2
 15062016 11:49
could you format it a bit better please
Tagged:Post rating:5 
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 3
 15062016 12:08
Hey guys
Was told to post my answers on a separate thread so it doesn't get lost in the other thread.
I've got my answers here:
Predicting 58 ish is an A and not much lower because it wasn't that bad of a paper. Loads of people thought it was OK or slightly harder. Theory questions threw me off a bit though.
Q1. 11 total i think
a) was Sdd or something (3)
b) wiggles is the response variable as it changes depending distance (1)
c) r = 0.722 + 0.014d
d) d= 350 sub in so w = 5.6 ish?
Q2 Sarah one
a) equation is 2p + q = 0.5
b) a= 0.175 b= 0.15
c) idk
d) E(R) = 0.45?
e) Sarah wins = 0.475 Rebeccawins= 0.375
Q3 with frequencies?
a) heigh of bar and width igot something like 34cm and 1cm?
b) show that Syy is … (1) didn’tdo this right lol
c) PMCC
d) SD
e) What were the other questions?
Q4 Hotel one
a) 0
b) t =0.03
c) u = 0.22
d) 0.45 and 15/37
e) diners 16? Some people say 33
Q5
a) median 3.47
b) SD = 0.689?
c) mean proof 3.43
d) Probability baby wasunder 3kg something like 0.2546
e) explain the use ofthe model? (2)I said that althoughthe range chosen was appropriate as mean was 3.43 for both and SD was close tothe calculated one, there is negative skew as median>mean so not good to use this model as mean and SD are affected by skew.
f) effect of adding baby weight of 3.43 on (3)
i) mean – I said staysthe same because I sneakily calculated it , because the frequency becomes 51and value is within range or something
ii) SD change "Others said it stayed thesame, but I wrote that it decreases, because now the average distance from themean is slightly less (as n has increased by 1 but deviance hasn't changed)".
Q6.
a) 0.0668 men took over 300 min to run
b) needs to run below 206.33 minutes to be in 20% of people who finish first
c)
d) the mew one0.18/0.5 = 0.36 (3)
Let me know what I'm missing and I've done wrong as well as the marks for each if you rememberLast edited by logicmaryam; 15062016 at 12:48.Post rating:3 
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 4
 15062016 12:08
Ok, I managed to get all my answers stored in my calculator at the end, this is what I got. Not 100% sure on all of them, but we can compare.
Question 1Spoiler:Question 2Showa. Show that
b. W  can't remember reasoning
c. 0.994
d. 0.0772 + 0.0142d
e. i. 5.69
ii. Reliable as the data was interpolated; it was within the rangeSpoiler:Question 3Showa. 2p + q = 0.5
b. q = 0.15
c. p = 0.175
d. 2.12
e. 0.45
f. i. 0.475
ii. 0.375Spoiler:Question 4Showa. 2.35
b. Show that
c. 133.9  possibly 131.9
d. 0.754
e. Increase  I tried using the variables from the new week and recalculating r, and it was higher than the original. I said because the values were both higher than the means; I'm not sure at all on this one.
Spoiler:Question 5Showa. 0
b. t = 0.03
c. u = 0.22
d. i. 0.45
ii. 15/37
e. 33 people have dinner (40*0.18) + (37*(15/37))Spoiler:Question 6Showa. Width 0.5, Height 17
b. 3.47 (median)
c. i. Show that
ii. Standard deviation = 0.680  possibly 0.689
d. P(W<3) = 0.2546
e. No  the mean is not equal to the median suggesting asymmetrical skew18% of babies were less than 3kg, but her model predicted 25.46%
f. i. Mean remains the same as the new value is the mean
note: mean might decrease as it adds a value to the 33.5 group.
ii. The standard deviation decreases as the variance decreases with a new value close to the meanSpoiler:Showa. 0.0668
b. 206  The lowest 20% of times were the fastest 20% of runners.
c. 0.36Last edited by veldt127; 15062016 at 14:11. Reason: Amended 5.f.iPost rating:17 
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 5
 15062016 12:10
(Original post by logicmaryam)
Hey guys
Was told to post my answers on a separate thread so it doesn't get lost in the other thread.
I've got my answers here:
Predicting 63+ is an A and not lower because it wasn't that bad of a paper. Theory questions threw me off a bit though.
Q1. 11 total i think
a) was Sdd or something (3)
b) wiggles is the response variable as it changes depending distance (1)
c) r = 0.722 + 0.014d
d) d= 350 sub in so w = 5.6 ish?
Q2 Sarah one
a) equation is 2p + q = 0.5
b) a= 0.175 b= 0.15
c) idkd) E(R) = 1/E(X) so 0.45?
e) Sarah wins = 0.475 Rebeccawins= 0.375
Q3 with frequencies?
a) heigh of bar and width igot something like 34cm and 1cm?
b) show that Syy is … (1) didn’tdo this right lol
c) PMCC
d) SD
e) What were the other questions?
Q4 Hotel one
a) 0
b) t =0.03
c) u = 0.22
d) 0.45 and 15/37
e) diners 16? Some people say 33
Q5
a) median 3.47
b) SD = 0.689?
c) mean proof 3.43
d) Probability baby wasunder 3kg something like 0.2546
e) explain the use ofthe model? (2)I said that althoughthe range chosen was appropriate as mean was 3.43 for both and SD was close tothe calculated one, there is negative skew as median>mean so not good to use this model as mean and SD are affected by skew.
f) effect of adding baby weight of 3.43 on (3)
i) mean – I said staysthe same because I sneakily calculated it , because the frequency becomes 51and value is within range or something
ii) SD – the SDincreases? Don’t remember. Because there are more values to be accounted for inthe calculation so spread is increased?
Q6.
a) 0.0668 men took over 300 min to run
b) needs to run below 206.33 minutes to be in 20% of people who finish first
c)
d) the mew one0.18/0.5 = 0.36 (3)
Let me know what I'm missing and I've done wrong as well as the marks for each if you rememberPost rating:1 
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 6
 15062016 12:11
nice, add some spoilers to each questions.
also, itd be a cool idea if you found out the marks of each question and put a strawpoll asking how many marks you got, that way we could guess grade boundaries a lot easier.Post rating:4 
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 7
 15062016 12:11
(Original post by logicmaryam)
Hey guys
Was told to post my answers on a separate thread so it doesn't get lost in the other thread.
I've got my answers here:
Predicting 63+ is an A and not lower because it wasn't that bad of a paper. Theory questions threw me off a bit though.
Q1. 11 total i think
a) was Sdd or something (3)
b) wiggles is the response variable as it changes depending distance (1)
c) r = 0.722 + 0.014d
d) d= 350 sub in so w = 5.6 ish?
Q2 Sarah one
a) equation is 2p + q = 0.5
b) a= 0.175 b= 0.15
c) idkd) E(R) = 1/E(X) so 0.45?
e) Sarah wins = 0.475 Rebeccawins= 0.375
Q3 with frequencies?
a) heigh of bar and width igot something like 34cm and 1cm?
b) show that Syy is … (1) didn’tdo this right lol
c) PMCC
d) SD
e) What were the other questions?
Q4 Hotel one
a) 0
b) t =0.03
c) u = 0.22
d) 0.45 and 15/37
e) diners 16? Some people say 33
Q5
a) median 3.47
b) SD = 0.689?
c) mean proof 3.43
d) Probability baby wasunder 3kg something like 0.2546
e) explain the use ofthe model? (2)I said that althoughthe range chosen was appropriate as mean was 3.43 for both and SD was close tothe calculated one, there is negative skew as median>mean so not good to use this model as mean and SD are affected by skew.
f) effect of adding baby weight of 3.43 on (3)
i) mean – I said staysthe same because I sneakily calculated it , because the frequency becomes 51and value is within range or something
ii) SD – the SDincreases? Don’t remember. Because there are more values to be accounted for inthe calculation so spread is increased?
Q6.
a) 0.0668 men took over 300 min to run
b) needs to run below 206.33 minutes to be in 20% of people who finish first
c)
d) the mew one0.18/0.5 = 0.36 (3)
Let me know what I'm missing and I've done wrong as well as the marks for each if you remember
i think it should be w=0.5 from comparing class width
area of given bar =4
A=kF
4=k8 k=0.5
so area of this bar =0.5x17=8.5
h=8.5/0.5=17 
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 8
 15062016 12:13
(Original post by veldt127)
Ok, I managed to get all my answers stored in my calculator at the end, this is what I got. Not 100% sure on all of them, but we can compare.
Question 1
a. Show that
b. W  can't remember reasoning
c. 0.994
d. 0.0772 + 0.0142d
e. i. 5.69
ii. Reliable as the data was interpolated; it was within the range
Question 2
a. 2p + q = 0.5
b. q = 0.15
c. p = 0.175
d. 2.12
e. 0.45
f. i. 0.475
ii. 0.375
Question 3
a. 2.35
b. Show that
c. 133.9
d. 0.754
e. Increase  I tried using the variables from the new week and recalculating r, and it was higher than the original. I said because the values were both higher than the means; I'm not sure at all on this one.
Question 4
a. 0
b. t = 0.03
c. u = 0.22
d. i. 0.45
ii. 15/37
e. 33 people have dinner (40*0.18) + (37*(15/37))
Question 5
a. Width 0.5, Height 17
b. 3.47 (median)
c. i. Show that
ii. Standard deviation = 0.680
d. P(W<3) = 0.2546
e. No  the mean is not equal to the median suggesting asymmetrical skew18% of babies were less than 3kg, but her model predicted 25.46%
f. i. Mean remains the same as the new value is the mean
ii. The standard deviation decreases as the variance decreases with a new value close to the mean
Question 6
a. 0.0668
b. 206  The lowest 20% of times were the fastest 20% of runners.
c. 0.36Post rating:2 
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 9
 15062016 12:15
(Original post by logicmaryam)
ii) SD – the SDincreases? Don’t remember. Because there are more values to be accounted for inthe calculation so spread is increased?Post rating:2 
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 10
 15062016 12:17
(Original post by KloppOClock)
nice, add some spoilers to each questions.
also, itd be a cool idea if you found out the marks of each question and put a strawpoll asking how many marks you got, that way we could guess grade boundaries a lot easier.
(Original post by SANTR)
Just out of interest how did you reach the answer for 2(e). What did you have to do to the given Probability Distribution table? 
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 11
 15062016 12:18
(Original post by veldt127)
Sorry, why do I need to spoiler answers? If someone's on this thread they'll want to see answers right? I'm new to this so sorry if there's another reason
I found the reciprocal of each score, then multiplied by the probability. Have to say I wasn't sure on that one. 
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 12
 15062016 12:18
1d is 5.7 to 2 sig figs

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 13
 15062016 12:18
(Original post by veldt127)
Sorry, why do I need to spoiler answers? If someone's on this thread they'll want to see answers right? I'm new to this so sorry if there's another reason
I found the reciprocal of each score, then multiplied by the probability. Have to say I wasn't sure on that one.Post rating:1 
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 14
 15062016 12:19
(Original post by veldt127)
Ok, I managed to get all my answers stored in my calculator at the end, this is what I got. Not 100% sure on all of them, but we can compare.
Question 1
a. Show that
b. W  can't remember reasoning
c. 0.994
d. 0.0772 + 0.0142d
e. i. 5.69
ii. Reliable as the data was interpolated; it was within the range
Question 2
a. 2p + q = 0.5
b. q = 0.15
c. p = 0.175
d. 2.12
e. 0.45
f. i. 0.475
ii. 0.375
Question 3
a. 2.35
b. Show that
c. 133.9
d. 0.754
e. Increase  I tried using the variables from the new week and recalculating r, and it was higher than the original. I said because the values were both higher than the means; I'm not sure at all on this one.
Question 4
a. 0
b. t = 0.03
c. u = 0.22
d. i. 0.45
ii. 15/37
e. 33 people have dinner (40*0.18) + (37*(15/37))
Question 5
a. Width 0.5, Height 17
b. 3.47 (median)
c. i. Show that
ii. Standard deviation = 0.680
d. P(W<3) = 0.2546
e. No  the mean is not equal to the median suggesting asymmetrical skew18% of babies were less than 3kg, but her model predicted 25.46%
f. i. Mean remains the same as the new value is the mean
ii. The standard deviation decreases as the variance decreases with a new value close to the mean
Question 6
a. 0.0668
b. 206  The lowest 20% of times were the fastest 20% of runners.
c. 0.36
2 f ii)
3 e) maybe I got one mark
4 d i)
4 e)
5 e) lost 12 marks
5 f ii)
6 c) maybe I got one mark for getting 0.5 as one of the probabilities.
Oh wells
Posted from TSR MobilePost rating:1 
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 15
 15062016 12:20
Hey everyone, I got 0.6 for 4.a (the hotel one), is it right?? I looked at the answers above it said 0 but I just guessed anyways

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 16
 15062016 12:21
3c> was 131.9 and 5 Cii> was 0.689
Post rating:1 
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 17
 15062016 12:21
(Original post by SANTR)
So you divided each of the observations by 1 and then multiplied the 'same' probabilities with each corresponding 'new' observation i.e. 1/ each observation?
(Original post by KloppOClock)
so it doesnt take up half the screen, its just nicer formattin 
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 18
 15062016 12:21
5f)i Didn't the mean decrease? It fell into the 33.5 one which had a midpoint of 3.25 which is less than the mean
Last edited by jackfgazeley; 15062016 at 12:24.Post rating:2 
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 19
 15062016 12:21
Q1: 2,1,2,4,2
Q2: 1,3,2,2,3,4
Q3: 3,1,2,2,2
Q4: 1,4,2,4,2
Q5: 3,2,3,3,3,3
Q6: 3,3,3
those were the marks for each part of the question.Post rating:11 
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 20
 15062016 12:22
(Original post by Jackhawkins21)
3c> was 131.9 and 5 Cii> was 0.689
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Updated: September 11, 2016
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