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# Edexcel Statistics 1 June 2016 Unofficial Mark Scheme

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1. Here is a very rough unofficial mark scheme.

Anything in bold is what I am unsure of and still need confirmation. I have missed out the explanation questions as well cant remember them.

If you know anything please let me know so I can add it in!
---------------------------------------------

1. (Bee wiggles)

PMCC = 0.99
b=?
a=?
estimate = 3.581

2. (Discrete Random Variables)
a) Making equation
b and c) q = 0.15 and p = 0.175
d) E(R) = 0.45
f) Couldn't do the last part

3. (Seatrop question)

s.d = 2.51 (I used the equation that represented the sample, not the population, so might be slightly different)
Sxy = -133.9
PMCC = -0.7

4. (Venn diagram question?)
a) 0
b) u = 0.03 t = 0.22
d) P(D|RnB) = 0.45 P(D|RnB' = 0.405
f) 16 students

5. (Baby question)

a) Width = 0.5 Height = 17
b) Median = 3.47
c) Mean = 3.43
d) Standard Distribution part i can't remember

6. (Normal Distribution)
a) ?
b) Maximum time was 206 minutes
c) P(W < u -30| W < u) = 0.36
2. What was the last part's question for #2?
3. (Original post by Sels97)
What was the last part's question for #2?
It was the one where you had to find the probability that sarah wins or rebecca wins
4. (Original post by SirRaza97)
It was the one where you had to find the probability that sarah wins or rebecca wins
IIRC Rebecca could only win when X was 1/2 and therefore she had a 0.2 chance of winning, whereas Sarah had a 0.8 chance.

I could be wrong, but this is the conclusion I came to
5. with that question i'm pretty sure there was the opportunity that they could draw too instead of winning/losing I think I got 0.65 for sarah and 0.2 for rebecca
6. 4 D) P(D|RnB) = 0.45 P(D|RnB') = 15/37
E) 33 People
7. (Original post by M3WIZARD)
4 D) P(D|RnB) = 0.45 P(D|RnB' = 15/37
E) 33 People
15/37 is the same as 0.405 just rounded. How did you get 33?
8. I got 16 for the people who will have dinner too
9. I got 33 people for dinner
10. I got 33. Also I don't think that the dimensions for the bar on the histogram is right? I didn't get that, but I could be wrong - always struggle with histograms.
11. (Original post by LordStark)
I got 33. Also I don't think that the dimensions for the bar on the histogram is right? I didn't get that, but I could be wrong - always struggle with histograms.
Mate I got 33 aswell. Always encouraging to hear that someone else got a similar answer. 😊
12. For 2f), I got that the probability Sarah wins is 0.475 and the probability Rebecca wins is 0.375.

From what i remember from my working out, Sarah can only win when X=3/2 and 2 so thats (0.3+0.175) and Rebecca can only win when X=-2 and 1/2 (0.175+0.2). There was a probability of drawing when X=-1 (0.15).

I could be wrong though. Did anyone else get this?
13. (Original post by Jorjio)
For 2f), I got that the probability Sarah wins is 0.475 and the probability Rebecca wins is 0.375.

From what i remember from my working out, Sarah can only win when X=3/2 and 2 so thats (0.3+0.175) and Rebecca can only win when X=-2 and 1/2 (0.175+0.2). There was a probability of drawing when X=-1 (0.15).

I could be wrong though. Did anyone else get this?
I got the same!
14. 1.) one question was which was the response variable, i said the number of bee wiggles is that right?
Also got something like w = 0.722 + 0.0142d for the regression line

4) last part i got 33 dinners, and i think thats right. you had to use the ratio of how many people ordered dessert to how many didn't from each of the two groups out of 77. There was a really similar question on one of the recent IAL papers

5f.) I said:
The mean and median are very similar = data is fairly symmetrical = good idea to use n.dis.
But worked out in part (d) that 25% of the babies weigh less than 3kg. Whereas the table showed that only 9/50 babies weighed less than 2 (=18%). Therefore Shyam should refine her model to make it more accurate.

6a.) what proportion finished in ?over/under? 300 minutes: 6.68%

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