It would help if you could link answers to questions as i cant remember them
Questions:
1) a)Asked to find dy/dx [2]
b) find dy/dx state value of p, p =2 [2]
c) find dy/dx[2]
2) a) show alpha lied between values [2]
b) rearrange to get into the form x=e^{(ln5 / x)} [3]
c) use iteration thingy where X_{1} = 2, X_{3} =2.054 [2]
d) simpsons rule on 5x^{x }limits of 1.7 to 0.5, 6 strips, answer = 4.49 to 2dp [4]
e) use d) to find approximate for x^{x }which was 1.51 (could someone explain how to do this please) [2]
3) a) solve x^{2 }>5x6 x<6, x>3 2>x>1 [5]
4) a) explain transformation of y=e^{x} onto y=e^{2x+5} stretch by 1/2 in xdirection and translation by (2.5,0) [4]
b) find area of triangle in the form (e^{2}+1)^{m} / e^{n} m = 2, n = 3 [6]
5) a) find range of f(x) = 16x  e^{2x} (differentiate, find stationary point) f(x)<8ln8  8 [5]
b) find gg(x) g(x) = 1/x therefore gg(x) = x [2]
6) a) integrate ( ln3x ) / x^{2} by using by parts twice [4]
b) volume of revolution, integrate ( ( ln3x ) /x^{2} )^{2 }limits of 1 to 1/3pi( (ln3)^{2}  2ln(3) +4 ) [7]
7) a) integrate using substitution (52x)(14x)^{1/3} using u=14x limits of 1/2 and 1/4 you get 177/224 [7]
8) a) use chain rule to show that (cosx)^{1} is secxtanx [2]
b) im sure this was a 2 marker?
c) find stationary point to get x value then sub into something to get y value which was root5 [4]
9)a) show secxtanx = 5 goes to secx+tanx=0.2 [2]
b) find the exact value of cosx cosx=1/2.6 [3]
c) solve the equation but x is changed into 2x70 with range of 90 to 90 [3]
i belive i jumbled up a few so pls correct and give CONFIRMED answers, ty.
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C3 Maths A2 AQA 2016 (unofficial mark scheme new)
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 1
 15062016 13:06
Last edited by username2592579; 15062016 at 14:13.Post rating:2 
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 2
 15062016 13:10
(Original post by beanigger)
It would help if you could link answers to questions as i cant remember them
Questions:
1) a)Asked to find dy/dx [2]
b) find dy/dx [2]
c) find dy/dx[2]
2) a) show alpha lied between values [2]
b) rearrange to get into the form [3]
c) use iteration thingy [2]
d) simpsons rule on 5x^{x} [4]
e) use d) to find approximate for x^{x }[2]
3) a) solve x^{2 }>5x6 [5]
4) a) explain transformation of y=e^{x} onto y=e^{2x+5} [4]
b) cant remember
5) a) find range of f(x) = 16x  e^{2x} [5]
b) find gg(x) [2]
6) a) integrate ( ln3x ) / x^{2} by using by parts twice [4]
b) volume of revolution, integrate ( ( ln3x ) /x^{2} )^{2 }[7]
7) a) integrate using substitution (52x)(14x)^{1/3} using u=14x limits of 1/2 and 1/4 [7]
8) a) use chain rule to show that (cosx)^{1} is secxtanx [2]
b) cant remeber
c) i think it was a 6 marker for the m = 2 and n = 3
9)a) show secxtanx = 5 goes to secx+tanx=0.2 [2]
b) find the exact value of cosx cosx=1/2.6 [3]
c) solve the equation but x is changed into 2x70 with range of 90 to 90 [3]
i belive i jumbled up a few so pls correct and give CONFIRMED answers, ty. 
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 3
 15062016 13:26
I believe the answer to the inequality was x>4, 1<x<2, x<6 Or something along those lines, where they're all strict inequalities?

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 4
 15062016 13:27
I feel like the area of the triangle question, which you've put as 8c, was earlier in the paper. I think maybe 6 and 8 may have been the other way around although I'm not too sure

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 5
 15062016 13:27
5a you can simplify anything in the form e^(a ln b) but I think I got f(x) <= 8 or something (not confirmed!)

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 6
 15062016 13:27
(Original post by JamesNuttall)
I believe the answer to the inequality was x>4, 1<x<2, x<6 Or something along those lines, where they're all strict inequalities? 
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 7
 15062016 13:30
(Original post by matty9)
5a you can simplify anything in the form e^(a ln b) but I think I got f(x) <= 8 or something (not confirmed!) 
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 8
 15062016 13:31
i swear it was 4>x>6 and 1<x and x>2
i drew that graph like 5 times and enlarged it, found that the above worked ? maybe im wrongPost rating:1 
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 9
 15062016 13:32
The question you wrote for 8c is actually for 4b. It was differentiating the y equation then working out A and B, where they cross the y and x axes. After it was working out the area of triangle OAB. Something along those lines. The answer you have is right (m=2 and n=3)
I think 8b or 8c (don't know if there was a 3rd part) was something about stationary points. You differentiated the equation, then worked out sinx and consequently cosx. Then you subbed these values back in for sec and tan and you get the y. Answer was root5 i think. 
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 10
 15062016 13:34
I redid question 5a and got the same answer as I did in the exam which was 8ln88
Can someone confirm my working?
Last edited by matty9; 15062016 at 13:35. Reason: cropped imagePost rating:1 
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 11
 15062016 13:34
(Original post by 3SwordStyle)
The question you wrote for 8c is actually for 4b. It was differentiating the y equation then working out A and B, where they cross the y and x axes. After it was working out the area of triangle OAB. Something along those lines. The answer you have is right (m=2 and n=3)
I think 8b or 8c (don't know if there was a 3rd part) was something about stationary points. You differentiated the equation, then worked out sinx and consequently cosx. Then you subbed these values back in for sec and tan and you get the y. Answer was root5 i think.Post rating:1 
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 12
 15062016 13:35
(Original post by beanigger)
It would help if you could link answers to questions as i cant remember them
Questions:
3) a) solve x^{2 }>5x6 *NEED CONFIRMED ANSWERS* [5]
5) a) find range of f(x) = 16x  e^{2x} (differentiate, find stationary point)
Question 4 coming momentarily...Post rating:5 
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 13
 15062016 13:36
(Original post by irMike)
I was already stressed by the time this question came up, When I saw it I was ready to give up completely. Didn't even see the remaining 4 questions either.
dy/dx = 16  2e^(2x) which = at a stationary point.
16 = 2e^(2x)
8 = e^(2x)
2x = ln(8)
x = ln(8)/2
d2y/dx2 = 4e^(2x)
when x = ln(8)/2, dy/dx is negetive, therefore it's a max point.
f(x) <= ln(8)/2 
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 14
 15062016 13:37
(Original post by irMike)
For the stationary point, did you get sin x = 2/3? A few people I spoke to got this, and none of us had any clue how this became a root? Had to keep it as a decimal in the end
Then subbing these into the orginal equation gave me 1/5 root 5 but I don't know how correct that is 
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 15
 15062016 13:38
(Original post by JamesNuttall)
y = 16x  e^(2x)
dy/dx = 16  2e^(2x) which = at a stationary point.
16 = 2e^(2x)
8 = e^(2x)
2x = ln(8)
x = ln(8)/2
d2y/dx2 = 4e^(2x)
when x = ln(8)/2, dy/dx is negetive, therefore it's a max point.
f(x) <= ln(8)/2 
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 16
 15062016 13:38
(Original post by irMike)
For the stationary point, did you get sin x = 2/3? A few people I spoke to got this, and none of us had any clue how this became a root? Had to keep it as a decimal in the end 
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 17
 15062016 13:38
(Original post by matty9)
I redid question 5a and got the same answer as I did in the exam which was 8ln88
Can someone confirm my working?

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 18
 15062016 13:39
(Original post by matty9)
I redid question 5a and got the same answer as I did in the exam which was 8ln88
Can someone confirm my working?

 Follow
 19
 15062016 13:39
(Original post by irMike)
For the stationary point, did you get sin x = 2/3? A few people I spoke to got this, and none of us had any clue how this became a root? Had to keep it as a decimal in the end 
 Follow
 20
 15062016 13:39
(Original post by irMike)
For the stationary point, did you get sin x = 2/3? A few people I spoke to got this, and none of us had any clue how this became a root? Had to keep it as a decimal in the end
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Updated: August 12, 2016
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