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# Need help with a C4 question

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1. https://www.jacktilson.uk/edu/maths/...-june-2006.pdf

How do I do 6B ? I looked at the mark scheme but it just gives the answer and I got no idea how they got it.
2. I got the X=3/2p and Y=0 and X=0,Y=3p^2

But how do i find PB and PA
3. (Original post by jeja12)
I got the X=3/2p and Y=0 and X=0,Y=3p^2

But how do i find PB and PA
Substitute x and y into the equation of the tangent,
4. (Original post by jeja12)
I got the X=3/2p and Y=0 and X=0,Y=3p^2

But how do i find PB and PA
PB and PA mean the lengths from P to B and P to A respectively. You could do this with trigonometry, or a formula which I think is introduced in Core 1.
5. So i tried to find PA using the equation and I got 1+2p^4 and PB=1+2p^3 but I feel thats wrong
6. nvm im an idiot. I got it thx

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