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pH calculations.

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Why bother with a post grad course - waste of time? 17-10-2016
    • Thread Starter

    Please can someone help explain the latter part of this question (b).

    I have worked out the pHs of the two individual solutions but am unaware in regard to finding the overall pH taking the volumes of these solutions into account.

    Any help is appreciated.
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    So since sodium hydroxide is a strong base, it neutralizes all the acid it comes into contact with. In these kind of situations you should calculate the moles of the base and the moles of the acid, subtract the moles of OH- from the moles of the acid, and then see what you got. In this case, you're only left with some OH-. After you've realized this the question should be pretty straightforward; you just figure out the new concentration of the ions (you know the number of moles left, and you can calculate the new volume) and calculate the pH from there.

    Hope this helps!
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