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# Moles!!!

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1. The formula for the production of ammonia in the haber process is as follows:
N2 + 3H2 ----> 2NH3

Molar mass
Nitrogen = 28
Hydrogen = 6
Ammonia = 34

How many moles are there in 2.8g of nitrogen?
number of moles = mass/molar mass =
2.8/28 = 0.1

How many moles of ammonia would form?
Ammonia has 2 moles so 0.1*2 = 0.2 moles would form

Work out the mass of ammonia formed.
0.2 * 34 = 6.8g

2. (Original post by Wolfram Alpha)
The formula for the production of ammonia in the haber process is as follows:
N2 + 3H2 ----> 2NH3

Molar mass
Nitrogen = 28
Hydrogen = 6
Ammonia = 34

How many moles are there in 2.8g of nitrogen?
number of moles = mass/molar mass =
2.8/28 = 0.1

How many moles of ammonia would form?
Ammonia has 2 moles so 0.1*2 = 0.2 moles would form

Work out the mass of ammonia formed.
0.2 * 34 = 6.8g

I'm pretty sure it's correct.

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3. (Original post by Firenze26)
I'm pretty sure it's correct.

Posted from TSR Mobile
4. check part (c)

28g of nitrogen makes 34g of ammonia. 1g of nitrogen forms 34/28 = 1.21g of ammonia.
So, 2.8g of nitrogen forms 2.8 * 1.21 = 3.388g = 3.4g of ammonia.

1 mole of N2 gives 2 moles of NH3

1 mole of anything is its RAM (Mr) in g

so 1 mole of N2 is 28g and 1 mole of NH3 is 17g

so 2.8g of N2 gives 3.4 g of NH3
6. (Original post by GDN)

1 mole of N2 gives 2 moles of NH3

1 mole of anything is its RAM (Mr) in g

so 1 mole of N2 is 28g and 1 mole of NH3 is 17g

so 2.8g of N2 gives 3.4 g of NH3
Oops, he is correct. I guess I couldn't do simple maths lol ammonia is 34g .

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