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# Fractional Indices

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1. (Original post by z_o_e)
Yayoo thank you so much

Can you introduce me to locais as that's coming up in tomorrow's end of yr exam.

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Oh locus isn't too difficult

if you have a dot like so . <-- then if the question says draw a locus around that dot you draw a circle because at all points the locus must be the same distance away from the point

not very good but you can see the locus around the dot is a circle yes?

the locus around a line is as shown below in the attachment

use a compass and draw the curve ok? don't do free hand like i did in paint xD

if you got any questions about locus just post them in the maths forum and someone will answer it ^-^
Attached Images

2. (Original post by fartinugget)
Oh locus isn't too difficult

if you have a dot like so . <-- then if the question says draw a locus around that dot you draw a circle because at all points the locus must be the same distance away from the point

not very good but you can see the locus around the dot is a circle yes?

the locus around a line is as shown below in the attachment

use a compass and draw the curve ok? don't do free hand like i did in paint xD

if you got any questions about locus just post them in the maths forum and someone will answer it ^-^
Oh okay )

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Attached Images

3. (Original post by z_o_e)
Oh okay )

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sure part 1 is testing if you know what mode means
Spoiler:
Show
the one with the greatest number of workers
part 2 is testing where the middle person is and which section of annual pay they fit into
Spoiler:
Show
add up all the no- of workers, divide by 2 and find which group the number falls into
(if you got a number 33 after you divide by 2 remember that the number 33 fits into the 14000<x<16000 pay because the 33rd person isn't in the 10000<x<14000 section anymore
part 3 is testing if you can work out a mean from the values given
Spoiler:
Show
take the middle value from the annual pay column (if the range is from 10000<x<14000 then the middle of those 2 values is 12000)
take that middle value and multiply it by the no. of workers in that column then do that for all the columns
once you have all those values add up all the no of workers
after you've gotten all that divide the middle value by the total no. of workers
(middle value x no of workers in that column)/total no. of workers
part 4 is testing why it's an estimate
Spoiler:
Show
i think that's because you used the middle value(midpoint) of all the annual pay
(don't forget that the spread of people won't always be equal within each annual pay section)
http://www.bbc.co.uk/bitesize/ks3/ma...ge/revision/8/

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Updated: June 19, 2016
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