Unofficial Markscheme:
Correct me if I'm wrong. The gaps are for answers I don't remember or questions.
1. 3x^2  20x [3]
2. a = 3, b = 20 [3]
3. (a) 12th term [2]
(b) 3/5 limiting factor [1]
4. (a)5, 8  basically it was opposite the numbers in the brackets [1]
(b) root 10  radius [1]
5. Prove the two line segments were perpendicular. AB gradient = 10/4 and BC gradients = 4/10, multiply the two gradients to get 1 so they are perpendicular.[3]
6. m = 8, p = 1 [4]
7. 9, 10, 11 [3]
8. x = 121 [3]
9. x^3  15x^2 + 75x  125 [3]
10. 80, x = 16 and y = 1/5 [4]
Should be 11. Circle theorem:
180  3x
2x + 58 = 2(180  3x)
2x + 48 = 360  6x
8x = 312
x = 39 [3]
12. (a) h = 3, k = 7 [2]
(b) 3, 7 [1]
(c) 3 +/ root 7 [1]
13. sqrt(125) + sqrt(20) = sqrt(80) + sqrt(x). Answer: x = 45 [3]
14. (a) When 3 is put into equation and a is 1, the equation is equal to 0. [2]
(x3)(x7)(x+2)  use long division first to get quadratic then factorise it [3]
15. 2root7  4 [3]
16. 5/6 for the cos and sine question [4]
17. k = 9 [5]
18. What Q? x^4  81 (I think it was this) = (x^2 + 9)(x+3)(x3) [I think 2 marks]
19. (a) Use pythagoras theorem, 9 + 9 = 18, side = root 18 = 3 root 2 [2]
(b) Trapezium  Idk, but I got the answer somehow: the bottom side of the triangle was root 3 and the hypotenuse was 2root3.
Add it all together: 3 + 3 + 3 + 2 root 3 + root 3 = 9 + 3 root 3, thats what u get when u expanded what they gave so it's correct. [4]
20. Cosine rule.
Cos P = 1/3.
Use the rule, you find u have to do 4/12 to get 1/3.
So, you do 13n^2  4n^2 = 9n^2
That's w^2 so w = 3n.
w = 3n same as the other side, so the triangle is isoceles. [4]
Well, I thought I had got really low, but after checking it again, it seems way better!
Harsh marking: 53/70
Lenient marking: 59/70
Well, I'm happy .
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Further Maths GCSE AQA Paper 1 (Unofficial mark scheme)
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 1
 20062016 13:34
Last edited by Chittesh14; 20062016 at 20:53.Post rating:3 
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 2
 20062016 13:57
I got 39 degrees for the circle theorems question
Post rating:1 
 Follow
 3
 20062016 14:20
(Original post by mattedwards8972)
I got 39 degrees for the circle theorems question
180  3x
2x + 58 = 2(180  3x)
2x + 48 = 360  6x
8x = 312
x = 39? 
 Follow
 4
 20062016 14:23
(Original post by Chittesh14)
Unofficial Markscheme:
Correct me if I'm wrong. The gaps are for answers I don't remember or questions.
3x^2  20x
12th term
3/5 limiting factor
5, 8  basically it was opposite the numbers in the brackets
Root 10?  radius
m = 8, p = 1
8 < x < 12
x = 55
x^3  15x^2 + 75x  125
80, x = 16 and y = 1/5
h = 3, k = 7
3, 7
3 +/ root 7
x = 45
When 3 is put into equation and a is 1, the equation is equal to 0.
(x3)(x7)(x+2)  use long division first to get quadratic then factorise it
2root7  4
5/6 or 5/6 ?
k = 9 apparently ( i missed it out)
Use pythagoras theorem, 9 + 9 = 18, side = root 18 = 3 root 2
Trapezium  Idk, but I got the answer somehow: the bottom side of the triangle was root 3 and the hypotenuse was 2root3.
Add it all together: 3 + 3 + 3 + 2 root 3 + root 3 = 9 + 3 root 3, thats what u get when u expanded what they gave so it's correct.
x^4  81 (I think it was this) = (x^2 + 9)(x+3)(x3)
Cosine rule.
Cos P = 1/3.
Use the rule, you find u have to do 4/12 to get 1/3.
So, you do 13n^2  4n^2 = 9n^2
That's w^2 so w = 3n.
w = 3n same as the other side, so the triangle is isoceles.
2.) Was the matrices question a=3 b= 20 ( if i remember correctly)
3.) Nth term is correct
cirlce question is correct
39 degrees is the answer to the circle theorem question
8<x < 12 is correct
For the x/y question y= 1/5 as it has to be less than 0
So the answer is 80
Completing square is correct
Surds is correct
Factor theorem is correct
5/6 is the correct for the cos theta question
K = 9 is correct
Trapezium question is solved using the 30,60 triangle and the 45,45 triangle . The diagnol side is 2 root 3 and the bottom is root 3
Factorising is correct
Isosceles proof is correct but i did it a different way
Posted from TSR Mobile 
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 5
 20062016 14:27
(Original post by ErinMei)
1.) Is right
2.) Was the matrices question a=3 b= 20 ( if i remember correctly)
3.) Nth term is correct
cirlce question is correct
39 degrees is the answer to the circle theorem question
8<x < 12 is correct
For the x/y question y= 1/5 as it has to be less than 0
So the answer is 80
Completing square is correct
Surds is correct
Factor theorem is correct
5/6 is the correct for the cos theta question
K = 9 is correct
Trapezium question is solved using the 30,60 triangle and the 45,45 triangle . The diagnol side is 2 root 3 and the bottom is root 3
Factorising is correct
Isosceles proof is correct but i did it a different way
Posted from TSR Mobile
x = 55 is right isn't it  the one with the bracket and to the power of 1/3 or something.Last edited by Chittesh14; 20062016 at 14:31. 
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 6
 20062016 15:13
which question gives x=55? That isn't right..you can't find square root of 55
(3root x)^1/3 = 2
3root x = (2)^3
3root x = 8
root x = 11
x = 121 
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 7
 20062016 15:15
There was a question related to completing the square in a quadratic equation and you were meant to answer in the form (a+sqrt.b).
What if you solved it by using the quadratic formula 
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 8
 20062016 15:19
Its fine. Remember it's just 1 mark (implying 1 minute) and a waste of your time using quad form. Moreso, you've done in in part a.

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 9
 20062016 15:19
With the question 8<x<12 apparently it asked for the integer values that x could be, i.e. 9,10,11
I put 8<x<12 but others said it asked for integers :/ 
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 10
 20062016 15:23
(Original post by Mr sss)
Its fine. Remember it's just 1 mark (implying 1 minute) and a waste of your time using quad form. Moreso, you've done in in part a. 
 Follow
 11
 20062016 15:23
(Original post by #1Mathlete)
With the question 8<x<12 apparently it asked for the integer values that x could be, i.e. 9,10,11
I put 8<x<12 but others said it asked for integers :/ 
 Follow
 12
 20062016 15:27
(Original post by Darshan98)
I dont think that question was 1 mark. And is it correct if you use the quad formula instead of completing the square?
12a...work out h and k........2 marks ....h=3....k= 7
12b....write down the coordinates of min point......1 mark ....(3,7)
And yes..its okay to use quad. form. 
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 13
 20062016 15:29
(Original post by Mr sss)
That's okay. It's the same. 8<x<12 is actually cool. Not used by anyone on the street. 
 Follow
 14
 20062016 15:39
(Original post by Darshan98)
There was a question related to completing the square in a quadratic equation and you were meant to answer in the form (a+sqrt.b).
What if you solved it by using the quadratic formula
(Original post by #1Mathlete)
It's not the same 8<x<12 is wrong as it's not the possible integer values, the actual answer is 9, 10 and 11
Lol I actually wrote 9, 10 and 11 on my rough paper ffs. 
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 15
 20062016 15:40
I've dropped from 6162 to around 56 OMG.

 Follow
 16
 20062016 15:42
(Original post by Chittesh14)
I've dropped from 6162 to around 56 OMG.
Posted from TSR Mobile 
 Follow
 17
 20062016 15:51
(Original post by Chittesh14)
Unofficial Markscheme:
Correct me if I'm wrong. The gaps are for answers I don't remember or questions.
3x^2  20x
a = 3, b = 20
12th term
3/5 limiting factor
5, 8  basically it was opposite the numbers in the brackets
Root 10  radius
m = 8, p = 1
8 < x < 12
x = 55
x^3  15x^2 + 75x  125
80, x = 16 and y = 1/5
h = 3, k = 7
3, 7
3 +/ root 7
Circle theorem:
180  3x
2x + 58 = 2(180  3x)
2x + 48 = 360  6x
8x = 312
x = 39
Another question: x = 45
When 3 is put into equation and a is 1, the equation is equal to 0.
(x3)(x7)(x+2)  use long division first to get quadratic then factorise it
2root7  4
5/6 for the cos and sine question?
k = 9
Use pythagoras theorem, 9 + 9 = 18, side = root 18 = 3 root 2
Trapezium  Idk, but I got the answer somehow: the bottom side of the triangle was root 3 and the hypotenuse was 2root3.
Add it all together: 3 + 3 + 3 + 2 root 3 + root 3 = 9 + 3 root 3, thats what u get when u expanded what they gave so it's correct.
x^4  81 (I think it was this) = (x^2 + 9)(x+3)(x3)
Cosine rule.
Cos P = 1/3.
Use the rule, you find u have to do 4/12 to get 1/3.
So, you do 13n^2  4n^2 = 9n^2
That's w^2 so w = 3n.
w = 3n same as the other side, so the triangle is isoceles. 
 Follow
 18
 20062016 16:05
For the inequality, t asked for integer solutions. Wouldn't you therefore have had to put 9, 10 and 11?
Other than that and question 6 (which I knew I'd completely messed up) I think I've done very well 
 Follow
 19
 20062016 16:06
Oh, also I didn't get +75x for the cubic, I got +25x. I'm probably wrong though haha

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 20
 20062016 16:07
Can someone explain the limiting factor one and how it was 3/5? I though it was 2.4 cos then the denominator would equal 0 and the fraction would be undefined
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Updated: June 28, 2016
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