In the mark scheme it says the distance travelled for part a is 20 meters whereas i think it should be sqrt 409. Could someone please explain to me why it is 20 meters? Any help is much appreciated!
The vertical distance to travel is 20m (Stated in the question as the width of the river) and you only have one vertical force which is 2sin(70) (This is found by equating the forces), hence as there is only one vertical force pushing the boat across the river and Speed = Distance over Time 2sin(70) = 20t Hence t = (2sin(70))/20
You're right in what you're saying that the distance traveled isn't 20m in total, but in terms of the vertical components, the boat only travels 20m
Also, good luck tomorrow, I'm sitting the same exam.