You are Here: Home >< Maths

# A Summer of Maths (ASoM) 2016

Announcements Posted on
Why bother with a post grad? Are they even worth it? Have your say! 26-10-2016
1. (Original post by physicsmaths)
Or parts on xsinx and secx

Posted from TSR Mobile
How so? Neither one of those has a nice anti-derivative.
2. (Original post by Zacken)
How so? Neither one of those has a nice anti-derivative.
Duno just running some **** through my head.

Posted from TSR Mobile
3. In a moment of weakness nearly ran it through wolfram alpha, almost

Posted from TSR Mobile
4. (Original post by Zacken)
How so? Neither one of those has a nice anti-derivative.
Easy zain. Took few minutes once i started writing. Pi/2(ln2)
Stop distracting me from d2 revision.
Need to pass otherwise im gna B in AFM.

Posted from TSR Mobile
5. Groups looks so bloody interesting *o*
6. (Original post by drandy76)
Unless I've goofed you end up were you started

Posted from TSR Mobile
Considering it's been posted on this thread by that person, I wouldn't expect anything less
7. (Original post by Student403)
Considering it's been posted on this thread by that person, I wouldn't expect anything less
I have two ideas and I'm too lazy to attempt either

Posted from TSR Mobile
8. (Original post by drandy76)
I have two ideas and I'm too lazy to attempt either

Posted from TSR Mobile
Na the obvious parts direction is roght. Just carry on going and note some symmetry.
A graph is symmetric about a if
F(2a-x)=F(x) or some simple symmetry of sin which is the same lol.

Posted from TSR Mobile
9. Will post sol if any mone wants it. Just dnt wana ruin it.

Posted from TSR Mobile
10. (Original post by Snasher350)
Substituting U=Cos x ? Should end up with a by parts integral with u and arccosU
Doesn't sound like it'll work.

(Original post by physicsmaths)
Will post sol if any mone wants it. Just dnt wana ruin it.

Did you basically end up finding integral of ln (sin x) between 0 and pi/2? If so, that wasn't really the intended method.
11. (Original post by physicsmaths)
Na the obvious parts direction is roght. Just carry on going and note some symmetry.
A graph is symmetric about a if
F(2a-x)=F(x) or some simple symmetry of sin which is the same lol.
Posted from TSR Mobile
ah i see, was considering taylor expansions lol
12. (Original post by Zacken)
Doesn't sound like it'll work.

Did you basically end up finding integral of ln (sin x) between 0 and pi/2? If so, that wasn't really the intended method.
Yeh. Not indefinite tho. Just added some **** and pi/2-x and u-pi/2 subs.
Here it is don't look anyone who hasn't solved yet, it is a very nice problem.

Was gna do a tanx method etc. Seems easier thenz

Posted from TSR Mobile
13. FWIW, my approach:

Now taking gives us and recovers .
14. (Original post by Insight314)
So many people got the Beardon, and I don't. I am furious!

I will have it in two days though.
I just had a look at the contents page on Amazon.

*goes to order the book*
15. (Original post by Zacken)
FWIW, my approach:

Now taking gives us and recovers .
Ah ok. Very nyc.
Shudda thought this was undergrad type ****.

Posted from TSR Mobile
16. Pesky people:

17. (Original post by Zacken)
Pesky people:

I got ln3 by considering I(a) = integral from 0 to 1 of e^(alnx)/lnx
18. (Original post by wlog54)
I got ln3 by considering I(a) = integral from 0 to 1 of e^(alnx)/lnx
The answer is correct, but I'm not entirely sure about your parametrisation. What do you need to recover the original integral? The only way I can see you move on from your parametrisation is by integrating the power series term by term, which isn't exactly savoury.

I'd use something like .
19. (Original post by Zacken)
The answer is correct, but I'm not entirely sure about your parametrisation. What do you need to recover the original integral? The only way I can see you move on from your parametrisation is by integrating the power series term by term, which isn't exactly savoury.

I'd use something like .
The parametrisation is fine. The required integral is .
20. Are any improvements on Dijkstra's Algorithm taught in Dx modules for x more or equal to 2?

## Register

Thanks for posting! You just need to create an account in order to submit the post
1. this can't be left blank
2. this can't be left blank
3. this can't be left blank

6 characters or longer with both numbers and letters is safer

4. this can't be left empty
1. Oops, you need to agree to our Ts&Cs to register

Updated: September 28, 2016
TSR Support Team

We have a brilliant team of more than 60 Support Team members looking after discussions on The Student Room, helping to make it a fun, safe and useful place to hang out.

This forum is supported by:
Today on TSR

### Who is getting a uni offer this half term?

Find out which unis are hot off the mark here

Poll
Useful resources