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# OCR (not MEI) S3 Statistics 3 - 29th June 2016

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1. Hi, noticed there wasn't a thread for this. What answers did everyone get?
2. in order apart from the confidence interval q one was a t interval right?
0.3306
30.48
1.969
15.01
0.2242
14586
3.512
8part ii was 0.707
3. (Original post by mkwhater)
in order apart from the confidence interval q one was a t interval right?
0.3306
30.48
1.969
15.01
0.2242
14586
3.512
8part ii was 0.707
I seem to remember having all of them.

I can't remember whether it was z or t - if the variance was known however, it would have been z
4. (Original post by Pinley)
I seem to remember having all of them.

I can't remember whether it was z or t - if the variance was known however, it would have been z
they gave you the standard deviation so I think it was z
5. (Original post by mkwhater)
in order apart from the confidence interval q one was a t interval right?
0.3306
30.48
1.969
15.01
0.2242
14586
3.512
8part ii was 0.707
what 3.512 and 0.2242 the answer to? I dont remember those questions
6. (Original post by Sid1234)
one of the last few q's i think it was chi squared can't remember
7. (Original post by mkwhater)
one of the last few q's i think it was chi squared can't remember
that was 3.911
8. Just tidying up the answers and adding a couple more, these are what I got anyway:

1) 0.331
2) Sum = 30.48 so reject H0.
3i) [0.0584, 0.262]
ii) [217, 231]
4) t = 1.9686 so reject H0.
5i) a = 9, b = 7
ii) variance = 15.0
6i) Z = 0.224 so accept H0.
ii) n = 14,586
7i) Show a = 12/31 or something.
ii) E(X) = 1.53
iii) didn't save my expected frequencies but ended up with 3.512 so accept H0.
8i) Something along the lines of for 0 < a < 400pi?
ii) 0.707

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Updated: June 29, 2016
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