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# Maths help

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1. How would I do this question?

"Rearrange y = 16 - 4x to make x the subject."
2. (Original post by Jack_Tomlin)
How would I do this question?

"Rearrange y = 16 - 4x to make x the subject."
How would you go about doing it?

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3. (Original post by Jack_Tomlin)
How would I do this question?

"Rearrange y = 16 - 4x to make x the subject."
Start by moving everything except 4x on one side, then divide through
4. (Original post by HopelessMedic)
Start by moving everything except 4x on one side, then divide through
Ok so far I've got - 16y = -4x
Is x = -4?
5. You should have taken 16 away from both sides to leave y-16=-4x. The divide through to get x in terms of y
6. (Original post by Jack_Tomlin)
Ok so far I've got - 16y = -4x
Is x = -4?
Remember that you are not solving for an actual value for x, you just want to find what x is in terms of y.
In your answer you correctly subtracted 16 from the RHS, but have not done the same on the LHS. Instead, you've multiplied the LHS by -16.
7. (Original post by surina16)
Remember that you are not solving for an actual value for x, you just want to find what x is in terms of y.
In your answer you correctly subtracted 16 from the RHS, but have not done the same on the LHS. Instead, you've multiplied the LHS by -16.
Ok would you mind answering the question so I can see all the steps?
8. (Original post by Jack_Tomlin)
Ok would you mind answering the question so I can see all the steps?
Sure.

y = 16 - 4x
[-16]
y - 16 = -4x
[*-1]
16 - y = 4x
[/4]
(16-y)/4 = x

you can leave it like that, or you can divide the 16 by the 4 to simplify it:
x = 4 - y/4
or
x = 4 - 0.25y which looks tidier imo
9. (Original post by surina16)
Sure.

y = 16 - 4x
[-16]
y - 16 = -4x
[*-1]
16 - y = 4x
[/4]
(16-y)/4 = x

you can leave it like that, or you can divide the 16 by the 4 to simplify it:
x = 4 - y/4
or
x = 4 - 0.25y which looks tidier imo
Thanks

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