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# How would I solve this equation?

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1. 2(6 - x) = 3(2x + 2)

I got x = 0.75
2. Expand brackets: 12-2x=6x+6
Solve as usual:
12 = 8x - 6. (Add 2x to each side)
18 = 8x. (Add 6 to each side)
x = 18/8
x = 2.25

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3. In my answer book it says -3?
(Original post by francesco_16)
Expand brackets: 12-2x=6x+6
Solve as usual:
12 = 8x - 6. (Add 2x to each side)
18 = 8x. (Add 6 to each side)
x = 18/8
x = 2.25

Thanks but in my answer book it says -3 is x? Strange

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4. (Original post by Jack_Tomlin)
2(6 - x) = 3(2x + 2)

I got x = 0.75
1. Expand brackets
Gives 12 - 2x = 6x +6

2. Put constants on one side, variables on the other
Gives 6 = 8x

3. Divide by the variable coefficient
Gives x = 0.75.

The book is either wrong or you have misread the question.
5. Sorry you was right I read it wrong I must have been tired last night The question was actually 2(6 - x) = 3(2x + 12)
(Original post by JLegion)
1. Expand brackets
Gives 12 - 2x = 6x +6

2. Put constants on one side, variables on the other
Gives 6 = 8x

3. Divide by the variable coefficient
Gives x = 0.75.

The book is either wrong or you have misread the question.
6. Is this right now?
(Original post by JLegion)
1. Expand brackets
Gives 12 - 2x = 6x +6

2. Put constants on one side, variables on the other
Gives 6 = 8x

3. Divide by the variable coefficient
Gives x = 0.75.

The book is either wrong or you have misread the question.
7. (Original post by Jack_Tomlin)
Is this right now?
Perfect

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