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C3 Simpllify Differentiation

Hi Guys I am struggling to see how the following equation simplifies as the answer on the bottom!

Can anyone show me where to start please?

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Reply 1
Avatar for B_9710
B_9710
18
=(3x+1)4[(3x+1)+15x] \displaystyle =(3x+1)^4 [(3x+1)+15x ] .
Just taking out the factor common to both terms. Then obviously simplify further to get the result.
(edited 7 years ago)
Reply 2
Avatar for MLW12345
MLW12345
OP
7
Original post by B_9710
=(3x+1)4[(3x+1)+15x] \displaystyle =(3x+1)^4 [(3x+1)+15x ] .
Just taking out the factor common to both terms. Then obviously simplify further to get the result.


hello thanks for the reply, I am trying to pull (3x+1)^4 as a common factor out but i'd really love to see 18 where that comes from?
(edited 7 years ago)
Reply 3
Avatar for JLegion
JLegion
2
Original post by MLW12345
hello thanks for the reply, I am trying to pull (3x+1)^4 as a common factor out but i'd really love to see 18 where that comes from?


In the square brackets you have:
[ (3x+1) + 15x ].

This can be simplified, as you have two sets of Xs, the 3x and the 15x. When you add them, you get 18x.
So your final result for the square brackets will be [ 18x + 1 ].
Reply 4
Avatar for MLW12345
MLW12345
OP
7
Original post by JLegion
In the square brackets you have:
[ (3x+1) + 15x ].

This can be simplified, as you have two sets of Xs, the 3x and the 15x. When you add them, you get 18x.
So your final result for the square brackets will be [ 18x + 1 ].



Got it thank you I could not see this until then thank you :smile:

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