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# Proof by induction

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1. (Original post by marioman)
The way you worded your post suggested that you didn't understand how it could be divisible by 2 whilst not having a 2 that can be taken out as a factor.
I was providing the example to show the OP that what he said wasn't necessarily true.
2. (Original post by marioman)
[...]
lol, you totally missed his point...
3. (Original post by marioman)
The way you worded your post suggested that you didn't understand how it could be divisible by 2 whilst not having a 2 that can be taken out as a factor.
It's ok, you misinterpreted what is said. Easy mistake to make.
4. (Original post by B_9710)
I was providing the example to show the OP that what he said wasn't necessarily true.
i not an intelligent man

which example of mine were you proving not always true?
(Original post by Zacken)
lol.Essentially you have 4 * (even number), so that's always divisible by 8 since it will always have a factor of 8 in it, to make that clear to the reader, you put it in the form 8g(k) so that the factor of 8 is apparent.
Ah ok thanks!
(Original post by B_9710)
is always divisible by 2 but doesn't have a 2 out that can be taken out as a factor seemingly.
So you have to make it obvious?

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