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New Maths GCSE 9-1 Sample Question Confused?!

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1. Anyone know how to solve this step by step
2. (Original post by NothingButWaleed)

Anyone know how to solve this step by step
Instead of telling you the answer, which you could probably find online. It'd be much more beneficial if you went through it step by step. Firstly, find a common denominator.
3. (Original post by NothingButWaleed)

Anyone know how to solve this step by step
3(x-1) + 4(x+2) = 12x(5)
3x - 3 + 4x +8 = 60x
5 = 53x
x =5/53
4. (Original post by NothingButWaleed)

Anyone know how to solve this step by step
You do, if you look at what your teacher taught you and apply it here.
5. Thanks for the help!
6. (Original post by NothingButWaleed)
Thanks for the help!
That's not help. Moreover, he wrote out the answer which is actually not allowed.
7. (Original post by EwanWest)
3(x-1) + 4(x+2) = 12x(5)
3x - 3 + 4x +8 = 60x
5 = 53x
x =5/53
But doesnt it turn into a quadratic?

Where does the "x" go when you do
3(x-1) + 4(x+2)???
8. (Original post by NothingButWaleed)
But doesnt it turn into a quadratic?

Where does the "x" go when you do
3(x-1) + 4(x+2)???
You are correct, to get a common denominator you need to times the tops and bottoms by the denominator of the opposing side it should be:

Numerators: 3x(x-1) + 4x(x+2)
Denominator: 4x(3x) + 3x(4x)

So you should get up with (after multiplying out the brackets):

3x²-3x/12x² + 4x²+8/12² = 5

Then, I recommend you add up the fractions, and get rid of the denominator. Then you end up with a quadratic
9. (Original post by Locyce)
You are correct, to get a common denominator you need to times the tops and bottoms by the denominator of the opposing side it should be:

Numerators: 3x(x-1) + 4x(x+2)
Denominator: 4x(3x) + 3x(4x)

So you should get up with (after multiplying out the brackets):

3x²-3x/12x² + 4x²+8/12² = 5

Then, I recommend you add up the fractions, and get rid of the denominator. Then you end up with a quadratic
What should I do after i get:
7x²+5x=60x²
10. (Original post by NothingButWaleed)
What should I do after i get:
7x²+5x=60x²
Get the equation equaling 0 and take out a common factor.

-53x2+5x=0

Take out that negative

-x(53x-5)=0

Then multiply by sides by -1, and you'll get a final answer.
11. (Original post by EwanWest)
3(x-1) + 4(x+2) = 12x(5)
3x - 3 + 4x +8 = 60x
5 = 53x
x =5/53
How about we don't give away full solutions? You may as well do his maths work for him at this rate.
12. Have you learn't how to solve a quadratic? If you haven't, you really need to get on that, perhaps one of the first things really. There are a few ways to solve a quadratic.

This is the format of a quadratic: ax²+bx+c=0 (Where a,b and c are integers, you must rearrange an equation to this format before trying to solve it)

According to the quadratic, it need to be solved in different ways - dependant on the situation:

1) When a=1 (eg. x²-3x-10=0)
2) When a is not = 1 (eg. 2x²-9x+4=0)
3) Completing the square
4) Graphically

Note: 1 and 2 is just a case of factorising, 3 is largely the same thing, but looks a little fancier and usually used in function questions, an A* topic

If you've learn't how to solve quadratics, reply to this comment and I'll go through it with you step by step. If you have, you can go ahead and attempt your original question.
13. (Original post by Locyce)
Have you learn't how to solve a quadratic? If you haven't, you really need to get on that, perhaps one of the first things really. There are a few ways to solve a quadratic.

This is the format of a quadratic: ax²+bx+c=0 (Where a,b and c are integers, you must rearrange an equation to this format before trying to solve it)

According to the quadratic, it need to be solved in different ways - dependant on the situation:

1) When a=1 (eg. x²-3x-10=0)
2) When a is not = 1 (eg. 2x²-9x+4=0)
3) Completing the square
4) Graphically

Note: 1 and 2 is just a case of factorising, 3 is largely the same thing, but looks a little fancier and usually used in function questions, an A* topic

If you've learn't how to solve quadratics, reply to this comment and I'll go through it with you step by step. If you have, you can go ahead and attempt your original question.
No need to form any quadratic's here. That would literally take longer, and one of the solutions wouldn't be valid when you solve it.
14. (Original post by Locyce)
You are correct, to get a common denominator you need to times the tops and bottoms by the denominator of the opposing side it should be:

Numerators: 3x(x-1) + 4x(x+2)
Denominator: 4x(3x) + 3x(4x)

So you should get up with (after multiplying out the brackets):

3x²-3x/12x² + 4x²+8/12² = 5

Then, I recommend you add up the fractions, and get rid of the denominator. Then you end up with a quadratic
I'm maths tutor that's correct
15. (Original post by RDKGames)
No need to form any quadratic's here. That would literally take longer, and one of the solutions wouldn't be valid when you solve it.
Of course! I've totally forgotten the last way! So sorry!

5) The Quadratic Equation, You must learn this off by heart, learn it better than your own name (In my maths teacher words)

Attachment 574472574474 Where a,b and c are integers from the original ax²+bx+c=0 format

If you need help explaining, I'm glad to help.
Attached Images

16. (Original post by Locyce)
Of course! I've totally forgotten the last way! So sorry!

5) The Quadratic Equation, You must learn this off by heart, learn it better than your own name (In my maths teacher words)

Where a,b and c are integers from the original ax²+bx+c=0 format

If you need help explaining, I'm glad to help.
I'm sorry but I think you missed my point?

Why are you explaining quadratics to him when he isn't even required to solve one?
17. (Original post by RDKGames)
I'm sorry but I think you missed my point?

Why are you explaining quadratics to him when he isn't even required to solve one?

Sorry, but I'm sure in GCSE maths, you'll need to solve a quadratic.

If you're referring to this specific question, perhaps you can give me some insight, I'm always happy to learn! (Even though it's summer break!)
18. (Original post by Locyce)
Sorry, but I'm sure in GCSE maths, you'll need to solve a quadratic.

If you're referring to this specific question, perhaps you can give me some insight, I'm always happy to learn! (Even though it's summer break!)
Yes, at GCSE you are required to solve quadratics, but not for this particular question.

Since OP already has the answer spoilt for him, here it is:

and solve it from there without much fuss of a quadratic.

IF we are going with a quadratic like your's and get to the stage of we can simply divide by x and get .

Before anyone jumps and says that we cannot divide by x, well we can. Only because in this particular scenario otherwise the original equation wouldn't make sense due to division by 0.
19. (Original post by RDKGames)
Yes, at GCSE you are required to solve quadratics, but not for this particular question.

Since OP already has the answer spoilt for him, here it is:

and solve it from there without much fuss of a quadratic.

IF we are going with a quadratic like your's and get to the stage of we can simply divide by x and get .

Before anyone jumps and says that we cannot divide by x, well we can. Only because in this particular scenario otherwise the original equation wouldn't make sense due to division by 0.

Ah, okay. Now i'm regretting losing all of that time at my GCSE Exam, but of course I did the easier old spec. This new 9-1 spec is going to be much tougher (though much more exciting)

20. (Original post by NothingButWaleed)

Anyone know how to solve this step by step
Pretty sure it's not a quadratic.

(Original post by NothingButWaleed)
But doesnt it turn into a quadratic?

You need to find the common denominator, which is 12x (response to

Where does the "x" go when you do
3(x-1) + 4(x+2)???

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