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Quick proportionality question

P inversely proportional to V

if P changes by 2/3 does this mean V changes by 3/2?
Reply 1
Avatar for TheCe
TheCe
8
Original post by khanpatel321
P inversely proportional to V

if P changes by 2/3 does this mean V changes by 3/2?


Nope

What's the question? As far as I know there's a constant which is either given or you have to calculate it using the information provided in the question.

Equation for this relation would be: P=k/v (k being the constant)
Original post by TheCe
Nope

What's the question? As far as I know there's a constant which is either given or you have to calculate it using the information provided in the question.

Equation for this relation would be: P=k/v (k being the constant)


Pressure is inversely proportional to volume.

Initial pressure = P0 Initial volume = V0

after a process the new pressure = 2/3(P0) What is the new volume?
Reply 3
Avatar for B_9710
B_9710
18
If you're talking about multiplying when you say change then yes. If P is inversely proportional to V then P=kV P=\frac{k}{V} (k is constant). If we replace V with 2V we get P=k2V P=\frac{k}{2V} and so P has halved.

Original post by khanpatel321
Pressure is inversely proportional to volume.

Initial pressure = P0 Initial volume = V0

after a process the new pressure = 2/3(P0) What is the new volume?
Original post by B_9710
If you're talking about multiplying when you say change then yes. If P is inversely proportional to V then P=kV P=\frac{k}{V} (k is constant). If we replace V with 2V we get P=k2V P=\frac{k}{2V} and so P has halved.


P is inversely proportional to V

Initial pressure = P0 Initial volume = V0

After process 1

Pressure P1 = (2/3) * P0 So is V1 = (3/2)V0

Thank you
Reply 5
Avatar for B_9710
B_9710
18
Original post by khanpatel321
P is inversely proportional to V

Initial pressure = P0 Initial volume = V0

After process 1

Pressure P1 = (2/3) * P0 So is V1 = (3/2)V0

Thank you


Yes.

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