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# plz help with this maths question

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1. (2x+1/2)/3 -1/2=(y-1)/2

3x-4y=1

plz help with this simultaneous equation
2. (Original post by p29)
2x+1/2
------------ -1/2=y-1/2
3
What exactly do you have to do? Find x in terms of y, or find y in terms of x?
3. (Original post by HapaxOromenon3)
What exactly do you have to do? Find x in terms of y, or find y in terms of x?
find what x and y is
4. (Original post by p29)
2x+1/2
------------ -1/2=y-1/2
3

plz help with this simultaneous equation

is it (2x+ 1/2)/(-1/2) = y - 1/2??????????????? if not please can you write it this way?
5. (Original post by p29)
find what x and y is
You have two variables but only one equation, so there are infinitely many possible values of x and y.
6. omg i forgot to write the second equation
7. plz help this is an equation from hell
8. (Original post by p29)
omg i forgot to write the second equation
OK, now we can solve it. Rearrange the first equation as (2x+1/2)/3 = y/2, and multiply by 6 to give 2(2x + 1/2) = 3y -> 4x - 3y = -1.
Now 4x - 3y = -1 becomes 16x - 12y = -4
And 3x - 4y = 1 becomes 9x - 12y = 3
So subtract these to give 7x = -7, i.e. x = -1, so -4 - 3y = -1 -> -3y = 3 -> y is also -1.
9. (Original post by HapaxOromenon3)
OK, now we can solve it. Rearrange the first equation as (2x+1/2)/3 = y/2, and multiply by 6 to give 2(2x + 1/2) = 3y -> 4x - 3y = -1.
Now 4x - 3y = -1 becomes 16x - 12y = -4
And 3x - 4y = 1 becomes 9x - 12y = 3
So subtract these to give 7x = -7, i.e. x = -1, so -4 - 3y = -1 -> -3y = 3 -> y is also -1.
thank you!!!
10. (Original post by ArafatQ)
My hand writing isn't particularly neat but here is the answer. Let me know if you need clarification.
Attachment 578056
Attachment 578056578058578000
thank you!!!!

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