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how to rearrange? and get x

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1. 1.
โ4โ(3โ๐ฅ)/(2โ๐)=(6โ5๐ฅ)/(โ๐+1)
2.
(2๐ฅ+5)/3+(๐ฅโ2)/5= 2๐ฅ
3.
4/(2๐ฅโ3)โ๐ฆ/(2โ๐ฅ)= 3๐ฅ โ 1
plzzz help
2. (Original post by p29)
1.
โ4โ(3โ๐ฅ)/(2โ๐)=(6โ5๐ฅ)/(โ๐+1)
2.
(2๐ฅ+5)/3+(๐ฅโ2)/5= 2๐ฅ
3.
4/(2๐ฅโ3)โ๐ฆ/(2โ๐ฅ)= 3๐ฅ โ 1
plzzz help
Add/subtract the fractions before multiplying both sides by the denominator.

Or multiply through the equations by the denominators. Then proceed to solve for x.
3. (Original post by RDKGames)
Add/subtract the fractions before multiplying both sides by the denominator.

Or multiply through the equations by the denominators. Then proceed to solve for x.
how do you add/subtract the fractions when there are different variables in the denominator?
4. (Original post by p29)
how do you add/subtract the fractions when there are different variables in the denominator?
Just algebraic manipulation.

If you let a, b, c and d equal anything you want; then
5. (Original post by p29)
1.
โ4โ(3โ๐ฅ)/(2โ๐)=(6โ5๐ฅ)/(โ๐+1)
Assuming you mean

Multiply both sides by .
6. (Original post by RDKGames)
Just algebraic manipulation.

If you let a, b, c and d equal anything you want; then
Isn't it?

EDIT:You just changed it.
7. (Original post by alexjones1994)
Isn't it?
Typo, I edited it before you posted that lol.
8. (Original post by Zacken)
Assuming you mean

Multiply both sides by .
no the -4 is on the fraction
9. (Original post by p29)
no the -4 is on the fraction
10. (Original post by Zacken)
thank you

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