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Enthalpy help

The standard enthalpy change of combustion of ethanol is -1371 kjmol-1. Calculate the mass of ethanol needed to heat 500cm3 of water by 25c

can someone help??
(edited 7 years ago)
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Reply 2
First I'd calculate the mass of water you have. Density = mass/volume, so mass = density * volume.

The density of water is 1000kgm-3, so we convert the volume of water, 500cm3, into m3, which is 500 x 10-6 or 5 x 10-4 m3. Multiplied together, this gives a mass of about 0.5kg.

From here, you can calculate the energy needed to heat the water by 25 degrees using Q=mcΔTQ=mc\Delta T where Q is the energy, m is the mass of water, c is the specific heat capacity of water, and ΔT\Delta T is the change in temperature.

Q=0.5418025=52250J=52.25kJQ = 0.5 * 4180 * 25 = 52250 J = 52.25 kJ

Now, you know that the energy provided when combusting 1 mole of ethanol is 1371 kJ. We only need 52.25 kJ, which by dividing means we need about 0.038 moles of ethanol.

Finally, you can use n=mmRn = \frac {m}{m_R} rearranged to m=nMrm = nM_r where MrM_r is the relative molecular mass of ethanol, about 46.

m=0.03846=1.75gm = 0.038 * 46 = 1.75g of ethanol

I think this is right anyway. Hope it helps!
Reply 3
Have a look at 'chemistry student teacher' on youtube. He has a couple of good videos on enthalpy that actually goes through similar calculations :smile: have a watch ans itll help im sure!!!
Original post by tomlfc
The standard enthalpy change of combustion of ethanol is -1371 kjmol-1. Calculate the mass of ethanol needed to heat 500cm3 of water by 25c

can someone help??


First of all I'd find out what one mole of ethanol weighs. C2H5OH = 46g.

After that you would associate this mass with the energy created when it burns as the enthalpy change of combustion is the energy change when mole of a substance burns in oxygen.
So 46g ---> -1371kj

Now I would do an Eh=CmDeltaT calculation to find out the energy need to increase the temperature of 500cm^3 of water by 25 degrees celsius. Note the mass of water has to be in litres when doing the calculation.
Eh=4.18x0.5x25 = -52.25kj

Then you would calculate the associated mass using the enthalpy of combustion.

-1371kj ---> 46g
-1kj ---> (46/1371)
-52.25kj---> (46/1381)x52.25
-52.25kj---> 1.75g

1.75g is needed to heat the 500cm^3 of water by 25 degrees celsius.


Posted from TSR Mobile
(edited 7 years ago)
Original post by Ed5
First I'd calculate the mass of water you have. Density = mass/volume, so mass = density * volume.

The density of water is 1000kgm-3, so we convert the volume of water, 500cm3, into m3, which is 500 x 10-6 or 5 x 10-4 m3. Multiplied together, this gives a mass of about 0.5kg.

From here, you can calculate the energy needed to heat the water by 25 degrees using Q=mcΔTQ=mc\Delta T where Q is the energy, m is the mass of water, c is the specific heat capacity of water, and ΔT\Delta T is the change in temperature.

Q=0.5418025=52250J=52.25kJQ = 0.5 * 4180 * 25 = 52250 J = 52.25 kJ

Now, you know that the energy provided when combusting 1 mole of ethanol is 1371 kJ. We only need 52.25 kJ, which by dividing means we need about 0.038 moles of ethanol.

Finally, you can use n=mmRn = \frac {m}{m_R} rearranged to m=nMrm = nM_r where MrM_r is the relative molecular mass of ethanol, about 46.

m=0.03846=1.75gm = 0.038 * 46 = 1.75g of ethanol

I think this is right anyway. Hope it helps!


Thank you! Pretty sure this is correct :smile:

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