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# Basic simultaneous question - I am stuck, please explain the solution to this!

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1. Simultaneous equation:

3x-2y=4
2x+3y=-6

So I multiplied the top by 3 and the bottom by 2 in order to get the Y's the same:

9x-6y=12
4x+6y=-12

And then the signs are different, so you add them together and get:

13x=0

How do you do this one? Is it as simple as x=0, so then you substitute x=0 into the equation to find out y?

Am I just derping?

SOrry for the dumb question.
2. (Original post by blobbybill)
Simultaneous equation:

3x-2y=4
2x+3y=-6

So I multiplied the top by 3 and the bottom by 2 in order to get the Y's the same:

9x-6y=12
4x+6y=-12

And then the signs are different, so you add them together and get:

13x=0

How do you do this one? Is it as simple as x=0, so then you substitute x=0 into the equation to find out y?

Am I just derping?

SOrry for the dumb question.
A good way to test your solution is to put it back into both of the original equations. After all, that's what you're finding
3. (Original post by SeanFM)
A good way to test your solution is to put it back into both of the original equations. After all, that's what you're finding
I ended up with x=0 and y=-2, which seems to be correct. Thanks, I just derped and got confused - I forgot X could be 0 and it would still be solvable.

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