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# Factorials

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1. Given that n is an integer such that 0<=n<=2012, what is the minimum value of:
(n!)^2 * (2012-n)!
?
2. (Original post by HapaxOromenon3)
Given that n is an integer such that 0<=n<=2012, what is the minimum value of:
(n!)^2 * (2012-n)!
?
Hint:

Treat it as a sequence, n=0, n=1,....

Consider the ratio of consecutive terms.

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