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# Quadratic equation question help plz

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1. 2x^4+14x^2+24
I got one solution but I don't know why the other solution is supposed to be 2(x^2+3) when I divided the equation by 2 at the beginning please help.
2. I can't tell what the question is
3. (Original post by CorpusLuteum)
I can't tell what the question is
its at the top
4. (Original post by p29)
its at the top
Is the quadratic equal to zero.
Are you only finding x? Why is there a Y.
Be more clear.
5. (Original post by p29)
2x^4+14x^2+24
I got one solution but I don't know why the other solution is supposed to be 2(x^2+3) when I divided the equation by 2 at the beginning please help.
As above, be more clear.

Are you solving ??? Or are you rearranging for something?

You let got up to which is almost correct.

So or

Hence or

Which gives you complex roots.
6. (Original post by p29)
its at the top
You're overcomplicating it - the solution should only really be three lines max.
Start with the equation, divide by 2, factorise it (as of course) and then solve. Just because the quadratic is in as opposed to doesn't mean you can't solve it in the normal way.
7. (Original post by RDKGames)
As above, be more clear.

Are you solving ??? Or are you rearranging for something?

You got up to

So or

Hence or

Which gives you complex roots.
=0 and I have to factorise it
8. (Original post by p29)
=0 and I have to factorise it
If you have to factorise it then you've already done it with the y's, so replace them with x2 and you're done.
9. (Original post by p29)
=0 and I have to factorise it
the book says that when it is factorised one of them will be 2(x^2+3) which i dont understand
10. ????
11. is the book wrong?
12. Okay what factorisation have you got so far?
13. (Original post by p29)
is the book wrong?
No. You have factored out a 2 at the start so you need to bring it back.

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