core 3 Differentiation equation of the normal
find the equation to the normal of the curve y = ( 1 + x) / (x^3 + 1), where x =1
is this correct?
y' = (1 - 3x^2 - 3) / x^3 + 1
y' = - 5/2
y-1 = 2/5 ( x-1)
2x - 5y + 3= 0
is this correct?
y' = (1 - 3x^2 - 3) / x^3 + 1
y' = - 5/2
y-1 = 2/5 ( x-1)
2x - 5y + 3= 0
(edited 7 years ago)
Original post by Custardcream000
find the equation to the normal of the curve y = ( 1 + x) / (x^3 + 1)
is this correct?
y' = (1 - 3x^2 - 3) / x^3 + 1
y' = - 5/2
y-1 = 2/5 ( x-1)
2x - 5y + 3= 0
is this correct?
y' = (1 - 3x^2 - 3) / x^3 + 1
y' = - 5/2
y-1 = 2/5 ( x-1)
2x - 5y + 3= 0
Your question is nonsense. Find the normal to the curve, at what point? Please provide the full question in the future.
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