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# Core 4 partial fractions

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1. Show that 3/(x-2) + 4/(x-1) = 7x -11/(x-2)(x-1). Therefore solve the equation 3/(x-2) + 4/(x-1) = 7/x; I've done the first but I just need a prompt on how to do the second bit, I know it's probably really simple
2. Try restating the given equation in the second part by replacing the LHS with what you found in the first part of the question. Then cross-multiply the denominators. Then rearrange all the terms onto one side and you'll either be left with a quadratic, or (maybe) the term in x^2 will be zero...

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Updated: September 23, 2016
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